The table and the graph each show a different relationship between the same two variables, x and y:

Mathematics

1 answer:

RideAnS [48]2 years ago

5 0

Equation of the table is given by
y - 210 = (280 - 210)/(4 - 3) (x - 3)
y - 210 = 70(x - 3)
y - 210 = 70x - 210
y = 70x

When x = 11, y = 70(11) = 770

Equation of the graph is given by
y = 110/2 x = 55x

When x = 11, y = 55(11) = 605

Therefore the value of y in the table is grater than the value of y in the graph by 770 - 605 = 165

You might be interested in

GUYS PLEASE HELP IM IN NEED I WILL MARK BRAINLIEST

jekas [21]

The answer would be 1/3 up 1 over 3.

6 0

2 years ago

Read 2 more answers

4x-y=10 and y=2x-2 answers

Brums [2.3K]

4x - y = 10, y = 2x - 2

4x - (2x -2) = 10

4x - 2x + 2 = 10

2x = 8

x = 4

4(4) - y = 10

-y = -6

y = 6

So x = 4 y= 6

Hope this helps!
Brainliest and a like is much appreciated!

6 0

2 years ago

Read 2 more answers

A public health official is planning for the supplyof influenza vaccine needed for the upcoming flu season. She wants to estimat

Marizza181 [45]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25$

And rounded up we have that n=421

Step-by-step explanation:

We know that the sample proportion have the following distribution:

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We assume that a prior estimation for p would be $\hat p =0.5$ since we don't have any other info provided. And replacing into equation (b) the values from part a we got: