1) -3
2) 6
3) 4
4) 2
5) 5
6) 5
7) 7
8) -3
9) 9
10) 6
11) -5
12) 0
Here are your answers may I please have the brainliest
Answer:
2 hours
Step-by-step explanation:
Slope represents the hourly rate.
Constant represents initial price.

Answer:
2 quarts of 100% antifreeze.
Step-by-step explanation:
5 quarts/ .40 * x/ 1
.40x= 5
x=2
see the attached figure with the letters
1) find m(x) in the interval A,BA (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100
2) find m(x) in the interval B,CB(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20
3)
find n(x) in the interval A,BA (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x
4) find n(x) in the interval B,CB(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30
5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44
6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72
for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72
<span> h'(x) = 1.44 ------------ > not exist</span>
Answer:
2x^2 + 2y^2 + 2z^2
Step-by-step explanation:
x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2
First step is to put all the same ones together
( FYI, xy and yx is the same thing, just like how
2 x 3 and 3 x 2 is the same thing) this time I'll bracket the groups to make it easier on the eyes
(x^2 +x^2) + (xy - xy) +( y^2 + y^2) + (yz - yz) +
(z^2 +z^2) + (zx - zx)
2x^2 + 2y^2 + 2z^2
All the others just cancel themselves out, for example, xy-xy
When anything minus themselves it will become 0