Answer:
which agrees with the first answer in the list of possible options.
Step-by-step explanation:
We can use the fact that the addition of all four internal angles of a quadrilateral must render 
. Then we can create the following equation and solve for the unknown "h":
Therefore the angles of this quadrilateral are:
Mean
: The average of all the data in a set.
Median
: The value in a set which is most close to the middle of a range.
Mode
: The value which occures most frequently in a data set.
12,9,12,11,10,18,7,19,13,19
Mean = 13 (Average)
Median = 12 (Middle)
Mode = 12, 19 (most common)
Let n be old painters time. Then the new painters are 2n. So:
1/n+1/2n=1/6
2+1=2n/6
2n=18
n=9
The old painters take 9 hours; the new ones take 18
☺☺☺☺
Answer:
$8.00
Step-by-step explanation:
The problem statement gives two relations between the prices of two kinds of tickets. These can be used to write a system of equations for the ticket prices.
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<h3>setup</h3>
Let 'a' and 'c' represent the prices of adult and children's tickets, respectively. The given relations can be expressed as ...
a - c = 1.50 . . . . . . . adult tickets are $1.50 more
175a +325c = 3512.5 . . . . . total revenue from ticket sales.
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<h3>solution</h3>
We are only interested in the price of an adult ticket, so we can eliminate c to give one equation we can solve for 'a'. Using the first equation, an expression for c is ...
c = a -1.50
Substituting that into the second equation, we have ...
175a +325(a -1.50) = 3512.50
500a -487.50 = 3512.50 . . . . . . simplify
500a = 4000 . . . . . . add 487.50
a = 8 . . . . . . . . . divide by 500
An adult ticket costs $8.
Yes, I'm getting C also!
Since it's asking for the left-endpoint Riemann Sum, you will only be using the top left point as the height for each of your four boxes, making -1, -2.5, -1.5, and -0.5 your heights. The bases are all the same length of 2. You don't include f(8) because you're not using right-endpoints, and that would also add another 5th box that isn't included in the 0 to 8 range.
