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mars1129 [50]
3 years ago
8

5x - 2 = 8x + 10 What is the steps

Mathematics
2 answers:
AveGali [126]3 years ago
5 0

Answer:

x= -4

Step-by-step explanation:

5x-2=8x+10

(add 2 to both sides)

5x=8x+12

(subtract 8x from both sides)

-3x=12

(divide both sides by -3)

x=-4

mr_godi [17]3 years ago
5 0

Answer:

x= -4

Step by Step:

So we have our problem here

5x-2=8x+10

First we must

add 2 to both sides

5x=8x+12

next we must

subtract 8x from both sides

-3x=12

finally we divide both sides by -3

hope this helps man

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What is an equation for the line that passes through (-2,-3) with a slope of -1/2?
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Convert to standard form by applying the distributive property and rearranging the terms.

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Suppose 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at
ANEK [815]

Answer:

We conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

Step-by-step explanation:

We are given that 462 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not read at a fourth grade level.

Further suppose 135 of 500 randomly selected college students said they would be embarrassed to truthfully admit they could not "do math" at a fourth grade level (like fractions).

<em>Let </em>p_1<em> = proportion of college students who would be embarrassed to truthfully admit they could not read at a fourth grade level.</em>

p_2<em> = proportion of college students who would be embarrassed to truthfully admit they could not "do math" at a fourth grade level.</em>

So, Null Hypothesis, H_0 : p_1-p_2 = 0  or  p_1= p_2     {means that there is not any significant difference in the proportion of all college students who would be embarrassed by these two admissions}

Alternate Hypothesis, H_A : p_1-p_2 \neq 0  or  p_1\neq p_2     {means that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions}

The test statistics that would be used here <u>Two-sample z proportion</u> <u>statistics</u>;

                       T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}  } }  ~ N(0,1)

where, \hat p_1 = sample proportion of college students who would be embarrassed to admit they could not read at a fourth grade level = \frac{462}{500} = 0.924

\hat p_2 = sample proportion of college students who would be embarrassed to admit they could not "do math" at a fourth grade level = \frac{135}{500} = 0.27

n_1 = sample of college students = 500

n_2 = sample of college students = 500

So, <em><u>test statistics</u></em>  =  \frac{(0.924-0.27)-(0)}{\sqrt{\frac{0.924(1-0.924)}{500}+\frac{0.27(1-0.27)}{500}  } }

                              =  28.28

The value of z test statistics is 28.28.

<u>Also, P-value of the test statistics is given by;</u>

          P-value = P(Z > 28.28) = Less than 0.0005%

<u></u>

<u>Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.</u>

Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that there is a significant difference in the proportion of all college students who would be embarrassed by these two admissions.

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