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Gemiola [76]
3 years ago
11

While shopping for clothes Jaclyn spent 38 less than 2 times what Daniel spent. Jaclyn spent $10. Writes and solve an equation t

o find how much Daniel spent. Let x represent how much Daniel spent.
How much did Daniel spend?
Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0
38-(2•x)=10 < equation
$14 < Dylan spent
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Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
7.
nikitadnepr [17]

Answer:

$46

Step-by-step explanation:

40(0.15) = 6 (this is the amount of the tip)

40 + 6 = 46 (add the tip to the bill)

7 0
4 years ago
Finish the lyric and name the song and artist (For fun)
nirvana33 [79]
“Only want people around that's gonna make me better”
3 0
3 years ago
Read 2 more answers
The scatter plot shows how many bugs, with and without wings, were found by students on a field trip. How many bugs with wings d
fiasKO [112]
Bugs with wings:

Q = 13
F = 11
G = 20
---------add
   = 44

answer

<span>B) 44</span>
8 0
4 years ago
Read 2 more answers
Please answer this if you can thank you :))
krek1111 [17]

<u>Answer:</u>

The variable that has the highest power is considered to be the degree of polynomials in an algebraic equation.

A column:

1) 4x^3 .

The degree is 3.

2)x^2+4.

The degree is 2.

3) x-2

The degree is 1.

B column:

1) 2x^2+1

The degree is 2.

2) x^2-x

The degree is 2.

3) x^3-5x^2+1

The degree is 3.

A×B columns:

While Multiplying two terms in a equation, if the variables are same then multiply the constant value and sum the exponent value.

1) (4x^3)(2x^2+1).

=8x^5+4x^3.

The degree is 5.

2) (x^2+4)(x^2-x).

=x^4-x^3+4x^2-4x.

The degree is 4.

3) (x-2)(x^3-5x^2+1).

=x^4-5x^3+x-2x^3+15x^2-3.\\=x^4-7x^3+15x^2+x-3.

The degree is 4.

3 0
3 years ago
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