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Nataly [62]
4 years ago
6

Determine if y=(1/5)^x is growth or decay

Mathematics
1 answer:
Nat2105 [25]4 years ago
7 0

The function f(x)=\left(\frac{1}{5}\right)^{x} is decaying.

<u>Step-by-step explanation:</u>

Given:

       f(x)=\left(\frac{1}{5}\right)^{x}

The above equation can also write as below,

    f(x)=\frac{1}{5^{x}}

Now from the function we can see that as we are increasing the value of x the value of function is decreasing.  Let take some values of x and then find out the value of function at those value of x

When x = 1 ,

         f(1)=\frac{1}{5}=0.2

When x = 2,

      f(2)=\frac{1}{5^{2}}=\frac{1}{25}=0.04

When x = 3,

      f(3)=\frac{1}{5^{3}}=0.008

So, from the above examples, we can see that the value of function is decreasing on increasing the value of x. Hence the function is decay

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4, Find a number x such that x = 1 mod 4, x 2 mod 7, and x 5 mod 9.
olchik [2.2K]

4, 7 and 9 are mutually coprime, so you can use the Chinese remainder theorem.

Start with

x=7\cdot9+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 4, the last two terms vanish and we're left with

x\equiv63\equiv64-1\equiv-1\equiv3\pmod4

We have 3^2\equiv9\equiv1\pmod4, so we can multiply the first term by 3 to guarantee that we end up with 1 mod 4.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 7, the first and last terms vanish and we're left with

x\equiv72\equiv2\pmod7

which is what we want, so no adjustments needed here.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 9, the first two terms vanish and we're left with

x\equiv140\equiv5\pmod9

so we don't need to make any adjustments here, and we end up with x=401.

By the Chinese remainder theorem, we find that any x such that

x\equiv401\pmod{4\cdot7\cdot9}\implies x\equiv149\pmod{252}

is a solution to this system, i.e. x=149+252n for any integer n, the smallest and positive of which is 149.

3 0
3 years ago
Help I guess? sorry I'm asking a lot of questions today
valina [46]

Answer:

63 houses have been sold this year.

Step-by-step explanation:

There are 81 houses in the community. If 7/9 are sold this year, then all you have to do is multiplication.

In this case, you would multiply 81 by 7/9 to get your answer.

81/1 x 7/9:

Cancel out the 9 and the 81. Then the denominator will be 1 x 1 and the numerator would be 7 x 9. It would be 63 (7x9=63) over 1 (1x1=1) which is just 63. Make sure to include units.

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3 years ago
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Answer:

d

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3 years ago
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Answer:

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Step-by-step explanation:

In March, Your Co. will collect 20% of January's sales, 30% of February's sales, and 50% of March's sales:

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Similarly, in April, collections will be ...

  .20×40 + .30×60 + .50×30 = 8 +18 +15 = 41

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Which expression below has the same value as

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