<span>The probability that a house in an urban area will develop a leak is 55%. if 20 houses are randomly selected, what is the probability that none of the houses will develop a leak? round to the nearest thousandth.
Use binomial distribution, since probability of developing a leak, p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000
</span>
Answer:
x(1 - .4)
Step-by-step explanation:
x = regular price.
1 - .4 = .6 = 60%
The sale price is equal to the full price (aka x) minus the discounted price (40% of x = 40/100 times x = .4x)
Therefore sale price = x - .4x or x(1 - .4)
Answer:
y=92
Step-by-step explanation:
Divided both sides by the numeric factor on the left side, then solve.
y = 92
X³ = -1000
x = ∛-1000
x = -10
In short, Your Answer would be: -10
Hope this helps!