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Sloan [31]
3 years ago
6

Plzzz help. Solve for x. Your answer must be simplified. 2x<15

Mathematics
2 answers:
tino4ka555 [31]3 years ago
5 0

For all values of x less than 7.5 the above inequality satisfies , i.e x

<u>Step-by-step explanation:</u>

Inequalities are the relationships between two expressions which are not equal to one another. The symbols used for inequalities are <, >, ≤, ≥ and ≠.

7 \textgreater x reads as '7 is greater than x' (or ' x is less than 7', reading from right to left).

x \leq -4 reads as ' x is less than or equal to -4' (or '-4 is greater than or equal to x', reading from right to left).

x \neq 5  reads as ‘ x is not equal to 5.

Here , we have

\begin{aligned}&2 x       { Dividing both sides by 2. }

∴ For all values of x less than 7.5 the above inequality satisfies.

ella [17]3 years ago
4 0

Answer:

x < 15/2

Step-by-step explanation:

To isolate x, let's divide both sides by 2.

2x/2 < 15/2        

Now, we simplify!

x < 15/2  

Hope this helps :D

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There are 25 the ratio of girls to boys is 3 to 2 how many boys and how many girls are in class
Serhud [2]

Answer:

Step-by-step explanation:

Girls:Boys = 3 : 2

Total students = 25

Girls = (3/5) * 25 = 15

Boys = (2/5) * 25 = 10

8 0
3 years ago
PLZ HELP, WILL GIVE BRAINLIEST!!!
fiasKO [112]

Answer: $4 senior, $7 child

Step-by-step explanation:

(3s + 9c = 75)

8s + 5c = 67

4 0
3 years ago
if something starts up costing 500, and then is marked down by 25% on rack of three separate occasions, what is the final price?
Fed [463]
The final price is $475 
5 0
3 years ago
A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro
pshichka [43]

Answer:

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed \frac{dx}{dt} = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}

(h)\frac{dh}{dt}=(x)\frac{dx}{dt}

(h)\frac{dh}{dt}=rx

\frac{dh}{dt}=\frac{rx}{h}

When automobile is 30 miles past the intersection,

For x = 30

\frac{dh}{dt}=\frac{30r}{h}

Since h=\sqrt{d^{2}+(30)^{2}}

Therefore,

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

3 0
3 years ago
Solve for u<br> 3(2u+5)=33<br> Simplify your answer as much as possible.
Pie
6u+15=33
6u=33-15
6u=18
u=3

U = 3 Is the answer!!!
HOPE THIS HELP!! :D
4 0
4 years ago
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