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AveGali [126]
3 years ago
10

12) A particular species of North American frog is most comfortable within a temperature range of 20 oC- 40 oC. A mating pair is

sitting ~2 feet apart. The female is in a puddle containing ~100 milliliters of water. The male is sitting on a fancy copper garden ornament that weighs ~400 grams. It is a very warm day, the temperature of both the ornament and water are 33oC. The sun’s rays provide an additional 10,000 Joules of energy to both the water and the ornamental perch. Which frog will be the first to move and join its mate? Use the following formula and values to justify your answer. q= msT 1 milliliter of water = 1 gram, s for water is 4.184 Joules/g/oC, s for copper is .387 Joules/g/oC
Business
1 answer:
meriva3 years ago
3 0

Answer:

The male frog would join the female frog in the water poodle

Explanation:

Mathematically,

Let x = temperature the 10000 joules from sun Ray would raise the temperature of the copper

So therefore:

10000 = m * (x - 33°) * Spc

Where m = mass of copper = 400g

Spc = specific heat capacity of copper = 0.387j/g/°c

So

400 * ( x - 33) * 0.387 = 10000

( x - 33 ) = 10000/ (400 * 0 387)

x = 97.6 °c

Temp for water where m = mass of water = 100g

x¹ = temperature the sun Ray of 10000 joules would raise the temp of water too.

Spw = specific heat capacity of water = 4.184j/g/°c

So therefore;

100 * ( x¹ - 33 ) * 4.184 = 10000joules

x¹ - 33 = 10000/ (100 * 4.184)

x¹ = 56.9°c

Since x for the male frog is greater than x¹ for the female frog, the male frog would be more uncomfortable because it's environmental temp is far higher than the comfort zone tem which is 20° to 40°c so it would move to join the female frog.

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Unless there is a table available, there is no explicit formula to calculate interest.  However, the interest rate can be solved for using the formula to calculate the monthly payment, as follows.

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A=\frac{26500(i*(1+i)^{60})}{(1+i)^{60}-1}
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