The equation of the exponential model is f(x) = 3 * 0.2^x
<h3>How to determine the exponential model?</h3>
The table of data is given as:
x(-2,-1,0,1,2)
f(x)(71,13,3,0.6,0.1)
An exponential model is represented as:
f(x) = ab^x
When x= 0 and f(x) = 3;
We have:
ab^0 = 3
This gives
a = 3
When x= 1 and f(x) = 0.6
We have:
ab^1 = 0.6
This gives
ab = 0.6
Substitute 3 for a
3b = 0.6
Divide both sides by 3
b = 0.2
Substitute b = 0.2 and a =3 in f(x) = ab^x
f(x) = 3 * 0.2^x
Hence, the equation of the exponential model is f(x) = 3 * 0.2^x
Read more about exponential model at:
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Answer:
y= -4 x+3
Step-by-step explanation: A(1, -1)
the equation is y - y (A)=m*( x-x(A) )
y-(-1)=-4(x-1)
y+1=-4x+4
y= -4x+4-1
y=-4x+3
y=-4x+4-1
The answer is x = 2 that's what I think
Check the picture below.
so the focus point is there, and the directrix is above it, meaning is a vertical parabola and is opening downwards, since the parabola opens up towards the focus.
now, the vertex is half-way between those two guys, at a "p" distance from either one, if we move over the y-axis from -5 to +2, we have 7 units, half-way is 3.5 units, and that puts us at -1.5 or -1½, as you see in the picture, so the vertex is then at (-3 , -1½).
so the distance from the vertex to the focus point is then 3½ units, however since the parabola is opening downwards, "p" is negative, thus "p = 3½".
![\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{using this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bparabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%204p%28x-%20h%29%3D%28y-%20k%29%5E2%20%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Busing%20this%20one%7D%7D%7B4p%28y-%20k%29%3D%28x-%20h%29%5E2%7D%20%5Cend%7Barray%7D%20%5Cqquad%20%5Cbegin%7Barray%7D%7Bllll%7D%20vertex%5C%20%28%20h%2C%20k%29%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf \begin{cases} h=-3\\ k=-\frac{3}{2}\\[0.7em] p=-\frac{7}{2} \end{cases}\implies 4\left( -\cfrac{7}{2} \right)\left[ y-\left(-\cfrac{3}{2} \right) \right]=\left[ x-\left( -3 \right) \right]^2 \\\\\\ -14\left( y+\cfrac{3}{2} \right)=(x+3)^2\implies y+\cfrac{3}{2} =-\cfrac{(x+3)^2}{14} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{14}(x+3)^2-\cfrac{3}{2}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20h%3D-3%5C%5C%20k%3D-%5Cfrac%7B3%7D%7B2%7D%5C%5C%5B0.7em%5D%20p%3D-%5Cfrac%7B7%7D%7B2%7D%20%5Cend%7Bcases%7D%5Cimplies%204%5Cleft%28%20-%5Ccfrac%7B7%7D%7B2%7D%20%5Cright%29%5Cleft%5B%20y-%5Cleft%28-%5Ccfrac%7B3%7D%7B2%7D%20%5Cright%29%20%5Cright%5D%3D%5Cleft%5B%20x-%5Cleft%28%20-3%20%5Cright%29%20%5Cright%5D%5E2%20%5C%5C%5C%5C%5C%5C%20-14%5Cleft%28%20y%2B%5Ccfrac%7B3%7D%7B2%7D%20%5Cright%29%3D%28x%2B3%29%5E2%5Cimplies%20y%2B%5Ccfrac%7B3%7D%7B2%7D%20%3D-%5Ccfrac%7B%28x%2B3%29%5E2%7D%7B14%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20y%3D-%5Ccfrac%7B1%7D%7B14%7D%28x%2B3%29%5E2-%5Ccfrac%7B3%7D%7B2%7D~%5Chfill)
Answer:A≈452.39cm
Step-by-step explanation:
