Access data is _______ in a Word document.

Write a Java program that will 1. Ask the user to type in a sentence, using a JOptionPane.showInputDialog(). 2. The program will

Paraphin [41]

Answer:

Here is the JAVA program :

import javax.swing.JOptionPane; //to use JOptionPane

public class Main { //class name

public static void main(String[] args) { //start of main method

int ECount= 0; //counts number of upper case E

int eCount= 0; //counts number of lower case e

String sentence; //stores input sentence string

sentence = JOptionPane.showInputDialog(null, "Type a sentence (type stop to exit)"); //uses showInputDialog method to display a dialog box which prompts user to enter a sentence

int length = sentence.length(); //stores the length of the sentence

while (!sentence.equalsIgnoreCase("stop")) //the loop continues to execute until the user types stop

{ for (int i = 0; i < length; i++) { //loops through the sentence

if (sentence.charAt(i) == 'E') //if the character is an uppercase E

ECount += 1; //adds 1 to the count of Ecount

if (sentence.charAt(i) == 'e') //if the character in a sentence is lowercase e

eCount += 1;} //adds 1 to the count of lower case e

JOptionPane.showMessageDialog(null, "There are " + ECount + " number of E's and " + eCount + " number of e's in " +sentence); //displays the number of times uppercase and lowercase (E and e) occur in sentence

sentence = JOptionPane.showInputDialog(null, "Type a sentence (type stop to exit"); //prompts user to enter the next sentence

length = sentence.length(); //stores the length of sentence at each iteration of while loop until user enters stop

eCount=0; //resets the counter of lowercase e

ECount=0; } } } //resets the counter of uppercase e

Explanation:

The program uses showInputDialog() method that displays a dialog box on output screen. This dialog box prompts the user to enter a string (sentence) Suppose user enters "Evergreen" as input sentence so

sentence = "Evergreen"

Next the length of this string is computed using length() method and stored in length variable. So

length = sentence.length();

length = 9

The for loop iterates through this input sentence until the variable i is less than length i.e. 9

At first iteration

if (sentence.charAt(i) == 'E') becomes

if (sentence.charAt(0) == 'E')

Here charAt() method is used which returns the character at the specified index i. This if condition is true because the character at 0-th index (first character) of the sentence Evergreen is E. So ECount += 1; statement adds 1 to the count of upper case E so

ECount = 1

At second iteration:

if (sentence.charAt(1) == 'E')

this condition is false because the character at 1st index of sentence is 'v' which not an upper case E so the program moves to next if condition if (sentence.charAt(i) == 'e') which is also false because the character is not a lower case e either.

At third iteration:

if (sentence.charAt(2) == 'E')

this condition is false because the character at 2nd index of sentence is 'e' which not an upper case E so the program moves to next if condition if (sentence.charAt(i) == 'e') which is true because the character is a lower case e. So the statement eCount += 1; executes which adds 1 to the count of e.

eCount = 1

So at each iteration the sentence is checked for an upper case E and lower case e. After the loop breaks, the program moves to the statement:

JOptionPane.showMessageDialog(null, "There are " + ECount + " number of E's and " + eCount + " number of e's in " +sentence);

which displays the number of uppercase E and lower case e in a message dialog box. So the output is:

There are 1 number of E's and 3 number of e's in Evergreen.

Then because of while loop user is prompted again to enter a sentence until the user enters "stop". Now the user can enter Stop, StOp, STOp etc. So equalsIgnoreCase method is used to cover all upper/lower case possibilities of the word "stop".

The screenshot of the program and its output is attached.

6 0

4 years ago

What type of socket should be used with an air impact wrench

Vikentia [17]

<span>Black sockets should be used, but the color is not the reason why. Chrome sockets will cause splits to form in the socket walls pretty quickly, after only a few uses. But the black sockets are that color because they have gone through a process called Parkerizing that coats the surface of the socket in order to provide more resistance when being used and protect the socket against corrosion.</span>

3 0

3 years ago

Was LDAP version2 an internet standard in 1998? is it now?

mamaluj [8]

Answer Explanation:

LDAP stand for lightweight directory access protocol 389 is its port number it is an application layer protocol it was first invented in march 1998 and become very popular widespread internet standard in august 1998 its authentication method is very simple the client send user name and password to LDAP server to access this.

4 0

3 years ago

Everyone within a company needs to be aware of what data can do to improve business processes and how to make it happen. Which c

OLga [1]

The concept that is been referred to in the statement above is known as data literacy.

<h3>What is data literacy?</h3>

The term data literacy is known to be man's ability to be able to read data, compose and share data. The understanding of data sources and how it works it all about data literacy.

Conclusively, when everyone in a firm are said to be data literate, There will be a lot of improvement in business processes of any firm.

Learn more about data literacy from

brainly.com/question/16514379

7 0

2 years ago

Write a recursive function, displayFiles, that expects a pathname as an argument. The path name can be either the name of a file

timama [110]

Answer:

Here is the Python function:

import os #module used to interact with operating system

def displayFiles(pathname): #recursive function that takes a pathname as argument

if (os.path.isdir(pathname)): #checks if specified path (argument) is an existing directory

for content in os.listdir(pathname): #gets the list of all files and directories in the directory and iterates through the items of this list of directory

contents = os.path.join(pathname, content) #joins contents of path

displayFiles(contents) #calls function recursively

else: #if pathname refers to a file

filename=pathname #sets filename to pathname

file = os.path.basename(filename) #gets base name in specified path

print("File Name: ", file) #displays the name of file

with open(filename, "r") as contents: #opens file in read mode

print("Content:") #prints Content:

for lines in contents: #iterates through the contents of file

print(lines) #displays the contents of file

Explanation:

The recursive function displayFiles contains a single argument pathname which can either be a pathname or a filename . If the given argument is pathname for directory , then the directory is opened and os.listdir returns a list containing the names of the entries in the directory given by pathname and append these contents in the list. Then this function is called recursively to print each file name and this function is applied to each name in the directory. However if the pathname refers to a file then the pathname is set to filename , the file is opened in read mode and the contents of the file are displayed.

8 0

4 years ago