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3 years ago

Access data is _______ in a Word document.

Computers and Technology

1 answer:

Naya [18.7K]3 years ago

5 0

I believe the answer is embedded. but make sure to check multiple sources.

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Assume a TCP sender is continuously sending 1,090-byte segments. If a TCP receiver advertises a window size of 5,718 bytes, and

Arturiano [62]

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

4 0

3 years ago

Write a code segment that takes an emailaddress stored in the string email and stores theuser name in the string user and the ho

iragen [17]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main() {

string email,username,host;//strings to store email,username,hostname..

cout<<"Enter the email address "<<endl;

cin>>email;//taking input of email address..

bool flag=1;

for(int i=0;i<email.length();i++)//iterating over the string email..

{

if(email[i]=='@')//if @ symbol is encountered make flag 0 skip this iteration.

{

flag=0;

continue;

}

if(flag==1)//add to username if flag is 1.

{

username+=email[i];

}

else//add tom host..

host+=email[i];

}

cout<<"The username is "<<username<<endl<<"The host name is "<<host;//printing the username and hostname..

return 0;

}

Explanation:

I have taken three strings to store the email address entered by user ,username and host to store username and host name respectively.Then I am iterating over the string email if @ is encountered then skip that iteration before that keep adding characters to username string and after that keep adding characters to host.

8 0

4 years ago

2) What are two reasons we analyze algorithms?

Likurg_2 [28]

It’s a making sections about what algorithms to use

8 0

3 years ago

Read 2 more answers

How can I become front end developer

yawa3891 [41]

The answer is by earn a recognized diploma get a guaranteed job.

8 0