$(3y^3+5y^2-4y) (2y^2-6y-7) \\=y(3y^2+5y-4)(2y^2-6y-7)\\=y(6y^4-16y^3-21y^2+10y^3-30y^2-35y-8y^2+24y+28)\\=y(6y^4-6y^3-59y^2-11y+28)\\=6y^5-6y^4-59y^3-11y^2+28y$

3 0

3 years ago

Solve t+m=r for r <br> pls help.

AlexFokin [52]

Hi!

<h3>So, we need to figure out what r equals. </h3>

r doesn't have to be a number. r has to equal a value. A value can be variables, or numbers, it doesn't matter.

<h3>The equation says r = t + m. Read the equation out loud. </h3>

<u>r equals t plus m. </u>

<h3>There's the value of r! </h3><h2>The answer is the problem: r = t + m</h2>

Hope this helps! :)

-Peredhel

4 0

4 years ago

Write 6 less than twice w as an algebraic expression

HACTEHA [7]

6 less than twice w

$2w-6$

5 0

4 years ago