Answer: t = 33
Step-by-step explanation:
t + 5 = 38
-5 -5 subtract 5 from both sides in order to isolate t
t = 33
Answer:
f(1) ≈ 2.7864
Step-by-step explanation:
You appear to want a couple of iterations of ...
... y[n+1] = y[n] +arcsin(x[n]·y[n]}·(x[n+1] -x[n])
... x[n+1] = x[n] +0.5
... x[0] = 0
... y[0] = 2
Filling in the values, we get
... y[1] = 2 + arcsin(0·2)·0.5 = 2
... y[2] = 2 + arcsin(0.5·2)·0.5 = 2 +(π/2)·0.5 ≈ 2.7864 . . . . corresponds to x=1
Answer: Choice D)
The angle between the two vectors is approximately 71.6 degrees
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Work Shown:
Each time I write the word "dot" I mean "dot product".
|u| = length of vector u
|u| = sqrt(u dot u)
|u| = sqrt(<8,4> dot <8,4>)
|u| = sqrt(8*8 + 4*4)
|u| = sqrt(64 + 16)
|u| = sqrt(80)
|u| = sqrt(16*5)
|u| = sqrt(16)*sqrt(5)
|u| = 4*sqrt(5)
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|v| = length of vector v
|v| = sqrt(v dot v)
|v| = sqrt(<9,-9> dot <9,-9>)
|v| = sqrt(9*9 + (-9)*(-9))
|v| = sqrt(81+81)
|v| = sqrt(2*81)
|v| = sqrt(2)*sqrt(81)
|v| = sqrt(2)*9
|v| = 9*sqrt(2)
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u dot v = <8,4> dot <9,-9>
u dot v = 8*9 + 4*(-9)
u dot v = 72-36
u dot v = 36
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cos(theta) = (u dot v)/(|u|*|v|)
cos(theta) = (36)/(4*sqrt(5)*9*sqrt(2))
cos(theta) = (36)/(36*sqrt(10))
cos(theta) = 1/(sqrt(10))
cos(theta) = sqrt(10)/10
theta = arccos(sqrt(10)/10)
theta = 71.56505
which rounds to 71.6 when rounding to one decimal place (nearest tenth)
That's why the approximate answer is roughly 71.6 degrees
Answer:
Jefferson High School
Step-by-step explanation:
so the same ratio would be 12 chaperones to 210 students....12/210 reduces to 2/35
18/300 reduces to 3/50
20/350 reduces to 2/35
8/160 reduces to 1/20
14/260 reduces to 7/130
So the same ratio would be Jefferson High School
Using the Pythagorean theorem
C = sqrt( 9^2 + 40^2)
C = sqrr(81 + 1600)
C = sqrt(1681)
C = 41 cm
