All categories

4 years ago

A constant net torque is applied to a rotating object. Which of the following best describes the object's motion?

Physics

1 answer:

Sphinxa [80]4 years ago

4 0

Answer:

f. The object will rotate with constant angular acceleration.

Explanation:

We know that

τ = I α

τ=Torque

I=Moment of inertia of the object

α =Angular acceleration

The moment of inertia is constant for an object and it does not depends on the applied torque.

If applied torque is constant then the angular acceleration of the object will be constant because moment of inertia is constant.

If angular speed is constant then the angular acceleration will,be zero.But in this case object is having angular acceleration that is why it have varying angular speed.

Therefore option "f" is correct.

You might be interested in

Would you expect to find a high or low level of resistance in a copper wire and why?

marysya [2.9K]

Low. Copper has relatively high conductivity.

4 0

4 years ago

What is an electromagnetic wave?

Sphinxa [80]

Answer:

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field.

6 0

3 years ago

HELP ASAP!

Leto [7]

Answer:

8kg

Explanation:

For the box to be in equilibrium. The clockwise moment ensued by the box on the right should be same as that ensued by the one on the right. Hence :

M ×3 = 12 ×2

M = 24/3 = 8kg

Note mass is used because trying to compute the weight by multiplying by the acceleration of free fall due to gravity on both sides will cancel out.

4 0

3 years ago

The bus, at location A, is traveling at 30 m/s when it is shifted to neutral and allowed to

sertanlavr [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The velocity of the bus at B is $v_B= 31.6\ m/s$

Explanation:

Let's take position B as base point .

From the diagram height between point B and A ia mathematically evaluated as

$h_A = 60 -55$

$h_A = 5 \ m$

From the question we are told that

The velocity at location A is $v_A = 30 m/s$

According the law of conservation of energy

$PE_A + KE_A = KE_B$

Where $PE_A$ is the potential energy at A which is mathematically represented as

$PE_A = mgh_A$

$KE_A$ is the kinetic energy energy at A which is mathematically represented as

$KE_A = \frac{1}{2} mv^2_A$

$KE_B$ is the kinetic energy at A which is mathematically represented as

$KE_B = \frac{1}{2} mv_B^2$

Where $v_B$ is the velocity at location B

$mgh_A + \frac{1}{2} mv_A^2 = \frac{1}{2} mv_B^2$

Making $v_B$ the subject of the formula

$v_B= \sqrt{\frac{gh_A + \frac{1}{2} v_A^2 }{0.5} }$

Substituting values

$v_B= \sqrt{\frac{(9.8 * 5) + \frac{1}{2} 30^2 }{0.5} }$

$v_B= 31.6\ m/s$

7 0

3 years ago

9. A motorcycle accelerates from 10. m/s to 55. m/s in 5.0 seconds. What is the average acceleration of the bike (provide reason

yuradex [85]

Answer:

9.0 m/s/s

Explanation:

Given the following data;

Initial velocity = 10 m/s

Final velocity = 55 m/s

Time = 5 seconds

To find the average acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation;

$a = \frac{55 - 10}{5}$

$a = \frac{45}{5}$

Acceleration, a = 9.0 m/s²

Therefore, the average acceleration of the motorcycle is 9 meters per seconds square because it's experiencing a uniform velocity or motion.

5 0

3 years ago