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muminat
2 years ago
10

Calculate f(4) for each function below

Mathematics
1 answer:
jeka57 [31]2 years ago
5 0
Subtitute x = 4 to the equations:

b)\ f(x)=\left(\dfrac{1}{5}\right)^x\to f(4)=\left(\dfrac{1}{5}\right)^4=\dfrac{1^4}{5^4}=\dfrac{1}{625}\\\\c)\ f(x)=3x-12\to f(4)=3\cdot4-12=12-12=0\\\\d)\ f(x)=(x-2)^3\to f(4)=(4-2)^3=2^3=8
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3. start fraction x over 5 end fraction + 6 = 10 (1 point) 44 30 20 –20 4. 3(4 – 2x) = –2x (1 point) –1 1 2 3
max2010maxim [7]

Answer:

3.x=20


Step-by-step explanation:


5 0
3 years ago
Find in degrees the numeric value of the acute angle of rotation that eliminates the product term from the equation 7x2+24xy−34x
lutik1710 [3]

Rotating the graph of Ax^2+Bxy+Cy^2+Dx+Ey+F=0 with B\ne0 counterclockwise by \theta eliminates the xy term, where \cot2\theta=\frac{A-C}{B}. Plugging in, we have \cot2\theta=\frac{7}{24}, since C=0. Solving, we have \theta=\frac{1}{2}\cot^{-1}(\frac{7}{24})\approx\boxed{36.9^\circ}.

4 0
3 years ago
Limit question: lim x-->pi ((e^sinx)-1)/(x-pi)
aleksandr82 [10.1K]
\displaystyle\lim_{x\to\pi}\dfrac{e^{\sin x}-1}{x-\pi}

Notice that if f(x)=e^{\sin x}, then f(\pi)=e^{\sin\pi}=e^0=1. Recall the definition of the derivative of a function f(x) at a point x=c:

f'(c):=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}

So the value of this limit is exactly the value of the derivative of f(x)=e^{\sin x} at x=\pi.

You have

f'(x)=\cos x\,e^{\sin x}\implies f'(\pi)=\cos\pi\,e^{\sin\pi}=-1
4 0
3 years ago
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
2 years ago
What is 9x-5-8+x= what
Elanso [62]
Hi there!

First you simplify.

Simplified = 9x+(−5)+(−8)+x

Then you combine the like terms.

<span><span><span><span><span>9x</span>+(<span>−5)</span></span>+(<span>−8)</span></span>+x (*-5 and -8 are like terms) (9x and x are like terms)

</span></span><span><span><span>Combined it's~ (<span><span>9x</span>+x</span>)</span>+<span>(<span><span>−5</span>+<span>−8</span></span>)

</span></span></span><span><span><span>Solve and that comes to 10x</span>+<span>−<span>13 which is your answer. :)

Hope this helps. 

</span></span></span></span>
3 0
2 years ago
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