Answer:
12
Step-by-step explanation:
I'm not entirely sure abt this but here goes nothing
75.36 divided by 3.14 = 24
24 = diameter
radius = 12
Answer:
A. 50°
Step-by-step explanation:
The external angle ACB created by tangents CA and CB is the supplement of arc AB it intercepts.
∠ACB = 180° -AB
∠ACB = 180° -130°
∠ACB = 50°
True because you do not include the number if the circle was open.
OK. I did it, and I have the solution.
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The length of the deck is (5 + 2x) .
The width of the deck is (4 + 2x) .
If the deck didn't have that big hole in the middle where the pool is,
then its area would be
(5 + 2x) · (4 + 2x) .
When you multiply that all out, you get Area = 4x² + 18x + 20
and the question tells us that the area of the whole big rectangle is 90 yds² .
So we can write
4x² + 18x + 20 = 90 .
Subtract 90 from each side: 4x² + 18x - 70 = 0
Divide each side by 2 : 2x² + 9x - 35 = 0
You can use the quadratic equation to solve that and find out that
x = 2.5 yards, and that's what the question is asking you.
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That makes the deck 10 yds high and 9 yds wide.
Total area of the whole big rectangle, (deck + pool ), = 90 yds².
Answer:
x=-3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3(x−6)+6=5x−6
(3)(x)+(3)(−6)+6=5x+−6(Distribute)
3x+−18+6=5x+−6
(3x)+(−18+6)=5x−6(Combine Like Terms)
3x+−12=5x−6
3x−12=5x−6
Step 2: Subtract 5x from both sides.
3x−12−5x=5x−6−5x
−2x−12=−6
Step 3: Add 12 to both sides.
−2x−12+12=−6+12
−2x=6
Step 4: Divide both sides by -2.
−2x
−2
=
6
−2
x=−3
