Answer:
1. 40.00 sq units
2. 37.5 sq units
Step-by-step explanation:
1. Given slant height as 3 and the square base side as 4,
-The surface area of a right squared pyramid is calculated by summing the areas of the 4 triangles and the square base:
![Area=Area \ Triangles+Base \ Area\\\\=4(\frac{1}{2}bh)+s^2\\\\=4(0.5\times 4\times 3)+4^2\\\\=24+16\\\\=40](https://tex.z-dn.net/?f=Area%3DArea%20%5C%20Triangles%2BBase%20%20%5C%20Area%5C%5C%5C%5C%3D4%28%5Cfrac%7B1%7D%7B2%7Dbh%29%2Bs%5E2%5C%5C%5C%5C%3D4%280.5%5Ctimes%204%5Ctimes%203%29%2B4%5E2%5C%5C%5C%5C%3D24%2B16%5C%5C%5C%5C%3D40)
Hence, the area of the square pyramid is 40.00 sq units
2. The surface area of a cube is equivalent to 6 times the side of one face.
-Given the dimension of the sides as 2.5, surface area is obtained as:
![A=6s^2\\\\=6(2.5\times2.5)\\\\=37.5](https://tex.z-dn.net/?f=A%3D6s%5E2%5C%5C%5C%5C%3D6%282.5%5Ctimes2.5%29%5C%5C%5C%5C%3D37.5)
Hence, the surface area of the cube is 37.5 sq units