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Hunter-Best [27]
3 years ago
5

1. Find the surface area of the square pyramid shown below?

Mathematics
2 answers:
Igoryamba3 years ago
8 0

Answer:

1. 40.00 sq units

2. 37.5 sq units

Step-by-step explanation:

1. Given slant height as 3 and the square base side as 4,

-The surface area of a right squared pyramid is calculated by summing the areas of the 4 triangles and the square base:

Area=Area \ Triangles+Base  \ Area\\\\=4(\frac{1}{2}bh)+s^2\\\\=4(0.5\times 4\times 3)+4^2\\\\=24+16\\\\=40

Hence, the area of the square pyramid is 40.00 sq units

2. The surface area of a cube is equivalent to 6 times the side of one face.

-Given the dimension of the sides as 2.5, surface area is obtained as:

A=6s^2\\\\=6(2.5\times2.5)\\\\=37.5

Hence, the surface area of the cube is 37.5 sq units

Ira Lisetskai [31]3 years ago
4 0

Answer:

40

Step-by-step explanation:

I got it correct on KHAN

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Solve V = twn for w.
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Answer:

\boxed{\bold{w \ = \ \frac{v}{nt} }}

Explanation:

  • Solve for 'w'

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Read 2 more answers
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

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When is it better to use a table in math
Galina-37 [17]

Answer:

in certain questions

Step-by-step explanation:

only use a table in Math when it is necessary. for example, when you are trying to find the coefficient.

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Daniela has the same amount of money automatically deposited into a new savings account each week. After 3 weeks, she has $18. A
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Answer:

$6 per week  (ratio 6/1)

Step-by-step explanation:

18/3=6

30/5=6

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