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spin [16.1K]
3 years ago
5

Write a recursive definition for the sequence 14, 10, 6, 2...

Mathematics
2 answers:
Anastasy [175]3 years ago
8 0

The answer is:

<h3>d. a_{1}=14, a_{n}=a_{n-1}-4</h3>

VladimirAG [237]3 years ago
7 0
The general form of recursive definition for arithmetic sequence:
a_{n}=a_{1}+d(n-1)

So, what we need to do is to find a_{1} and d.
a_{1}=14
d=a_{2}-a_{1}=10-14=-4
Having found these two values we can now define our recursive sequence:
a_{n}=14-4(n-1)
a_{n}=14-4n+4
a_{n}=18-4n
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A medical delivery service charges $10 for a house call plus 0.50 per mile. The situation is represented by the equation y=0.5+1
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Answer:

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3 years ago
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Which of the following sets of data will have the smallest Standard Deviation?
uranmaximum [27]

Answer: D

Step-by-step explanation:

Standard Deviation σ2 =

Σ(xi - μ)2/N

=(1 - 5.3)2 + ... + (9 - 5.3)2/10

=68.1/10

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σ = √6.81

= 2.60959767014

B) σ2 =

Σ(xi - μ)2/N

=(3 - 61.7)2 + ... + (99 - 61.7)2/10

=58414.1/10

= 5841.41

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C) (1 - 11.4)2 + ... + (1 - 11.4)2/10

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= 875.84

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D) (79 - 79)2 + ... + (79 - 79)2/10

=0/10

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6 0
3 years ago
What’s the slope of (5,9) and (8,4)
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Answer: -5/3

Step-by-step explanation:

Use the slope formula: \frac{y_{2}-y_1 }{x_2-x_1}

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3 years ago
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HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid
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Answer:  Missing parts are,

In first blank,  AD\cong DC,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

\angle BDA\cong \angle BDC ( right angles )

BD\cong BD ( reflexive)

Thus, By SAS ( side angle side )postulate,

\triangle ADB\cong \triangle CDB

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

AB\cong CB

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

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7 0
2 years ago
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