Step-by-step explanation:
vv
The vertex-form equation is
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 =
{-5, 3}
Answer:
Step-by-step explanation:
a) Here, the first term is .48 and the common ratio is 1/100 (since each new 48 is 1/100 th of the previous 48). a
Use the formula s = sum of geometric series = -----------
1 - r
0.48 48
which in this case is s = --------------- = ------------ = 48/99 = 16/33
1 - 1/100 100 - 1
Check this result by finding 16/33 on a calculator. Is the result equal to 0.484848484848.... ? Yes
b) Here we have the bar over the 8 only. 0.48 with the bar over the 8 is equivalent to 0.4888888888 ...
0.08
or 0.4 + 0.0888888888 ... or 0.4 + ------------
1 - 1/10
0.08 8
and this simplifies to 0.4 + ------------ = 0.4 + ---------
9/10 90
Evaluating this last result on a calculator results in 0.488888888 ...
c) 0.48 expressed as a fraction is 48/100 = 12/25
Answer:
Relation 1 : Not a function
R2 : Function
R3: Function
R4: Not a function
Answer:
see explanation
Step-by-step explanation:
To find the zeros let p(x) = 0 , that is
(x² - 1)(x² - 5x + 6) = 0
Factorise each factor
x² - 1 ← is a difference of squares and factors as (x - 1)(x + 1)
x² - 5x + 6 = (x - 2)(x - 3), thus
(x - 1)(x + 1)(x - 2)(x - 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
x + 1 = 0 ⇒ x = - 1
x - 2 = 0 ⇒ x = 2
x - 3 = 0 ⇒ x = 3
The zeros are x = ± 1, x = 2, x = 3