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kotykmax [81]
3 years ago
13

Which port must be open on your router to allow you to upload device configuration and firmware updates using trivial file trans

fer protocol to your devices throughout the internetwork?
Computers and Technology
1 answer:
Vika [28.1K]3 years ago
3 0

Answer:

UDP Port 69

<em>Trivial file transfer protocol (TFTP) operates over UDP port 69.</em>

Explanation:

UDP port 69 uses the Datagram Protocol, a communications protocol for the Internet network layer, transport layer, and session layer. This protocol when used over PORT 69 makes possible the transmission of a datagram message from one computer to an application running in another computer. UDP is used with <em>IP (the Internet Protocol)</em> and UDP Port 69 is <em>connectionless </em>which means it does not give reliable communication; it’s up to the application that received the message on Port 69 to process any errors and verify correct delivery.

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Answer:

The description for the given question is described in the explanation section below.

Explanation:

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3 years ago
People are starting to type in whole questions rather than specific words, which leads credence to having _____ that have this a
SpyIntel [72]

Answer:

a. corporate blogs

Explanation:

corporate blog is the practice of creating content that addresses various topics which includes (updates, expert tips or best practices and company news) from the perspective of a brand. Also, blogs make posts and comments easy to reach and follow.

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3 years ago
What was the first Apple computer, and who was it designed by?
DerKrebs [107]

Answer: The first Apple Computer was Apple 1. The designer was Steve Wozniak.

Explanation: Steve Wozniak and Steve Jobs both created Apple 1. Mainly, Steve Wozniak designed it.

Hope this helps!

7 0
3 years ago
Read 2 more answers
Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
3 years ago
B. Does “refactoring” mean that you modify the entire design iteratively? If not, what does it mean?
Liono4ka [1.6K]

Explanation:

Refactoring consists of improving the internal structure of an existing program's source code, while preserving its external behavior. 

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3 years ago
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