Answer:
1 + 2sqrt(3)/3
Step-by-step explanation:
tan(30) = sqrt(3)/3
sin(90) = 1
tan(60) = sqrt(3)
cot(60) = 1/sqrt(3) = sqrt(3)/3
sqrt(3)/3 + 1 + sqrt(3)/3
1 + 2sqrt(3)/3
Let's use 50 cents as the price of the item
Two for the price of one = $.50 for two (or $.25 each)
Three for the price of two = $1.00 for 3 or approximately $.33 each
Buy one get 25% off the 2nd means $.50 + (.125 which is 25% of $.50) for a total of $.625 or about $.63 ($.315 or about $.32 each)
Buy Two get 50% off the 2nd means $.50 for the first and $.25 for the 2nd for a total of $.75 or $.375 - about $.38 each
We can see that two for the price of one is the best value since you save $.25 off of $.50 (that's half) and that buy two get 50% off the 2nd is the smallest price reduction since the $.50 item only goes down to $.38 or twelve cents off.
This would work no matter what the cost of the item. The savings would still be in the same proportions.
They had a total of 45$ Steve got 18 Carl got 27
Answer:
(D)8 m, 5 m, 6 m, 6 m
Step-by-step explanation:
Answer:
There are 33 quarters and 47 dimes
Step-by-step explanation:
Let the number of quarters be q.
Let the number of dimes be d.
There are 80 coins in total. Therefore:
q + d = 80 ________(1)
The total value of coins is $13.
The value of a quarter is $0.25 and the value of a dime is $0.10. This means that:
0.25q + 0.10d = 13 _____(2)
We have a system of equations:
q + d = 80 ________(1)
0.25q + 0.10d = 13 ____(2)
From (1):
q = 80 - d
Put this in (2):
0.25(80 - d) + 0.10d = 13
20 - 0.25d + 0.10d = 13
Collecting like terms:
-0.15d = 13 - 20
-0.15d = -7
d = -7 / -0.15
d ≅ 47
Therefore:
q = 80 - 47 = 33
There are 33 quarters and 47 dimes.
