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3 years ago

You are a mechanic. You have been given an engine job time of 0.7 hour about how many minutes should you allow for the job

Mathematics

1 answer:

vitfil [10]3 years ago

6 0

I would allow 42 minutes for the job

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Please answer this correctly

BabaBlast [244]

Answer:

19.63

Step-by-step explanation:

If the radius is 5 centimeters, then the area is just 3.14*5^2 / 4, which is 78.5/4. This is equal to 19.625. Rounding this give us 19.63 as the final answer

8 0

2 years ago

Pablo's retirement party will cost $8 if he invites 4 guests. If there are 6 guests, how

mezya [45]

Answer:

$12

Step-by-step explanation:

Step 1:

$8 : 4 = x : 6

Step 2:

4x = 48

Answer:

x = 12

Hope This Helps :)

6 0

3 years ago

What is the equation of a line with a x-intercept of −2 and a y-intercept of 10?

IceJOKER [234]

Hey there! :)

Answer:

y = 5x + 10

Step-by-step explanation:

From the information given, we can derive the points (-2, 0) and (0, 10). Find the slope using the slope formula:

$m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}$

Plug in the points:

$m= \frac{10 - 0}{0 - (-2)}$

Simplify:

$m= \frac{10}{2}$

m = 5.

The equation in slope-intercept form is y = mx + b. We were already given the b value, or y-intercept as y = 10. Therefore:

y = 5x + 10 is the equation written in slope-intercept form.

8 0

2 years ago

Read 2 more answers

If the price of a purse went from $45 to $54, what was the percent of the change?

NARA [144]

I think the answer is 17%

7 0

3 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

4 0

3 years ago