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Svetllana [295]
3 years ago
5

A group of students were asked if they carry a credit card. The responses are listed in

Mathematics
1 answer:
Stels [109]3 years ago
3 0
Part of the question is missing
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Help pls look at question, I'm confused so yeah.
lions [1.4K]

Answer

225 ml

Step-by-step explanation:

90 ml =2 parts

1 part=45

5 parts= 225

5 0
3 years ago
The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi
storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

V = \frac{1}{3}\pi r^{2}h

Differentiate the equation with respect to time t, such that

\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)

To differentiate the product,

Let r² = u, so that

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)

Then, using product rule

\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]

Since u = r^{2}

Then, \frac{du}{dr} = 2r

Using the Chain's rule

\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}

∴ \frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]

Then,

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

Now,

From the question

\frac{dr}{dt} = 7 m/min

\frac{dV}{dt} = 236 m^{3}/min

At the instant when r = 99 m

and V = 180 m^{3}

We will determine the value of h, using

V = \frac{1}{3}\pi r^{2}h

180 = \frac{1}{3}\pi (99)^{2}h

180 \times 3 = 9801\pi h

h =\frac{540}{9801\pi }

h =\frac{20}{363\pi }

Now, Putting the parameters into the equation

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]

236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]

708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}

708 = 30790.75 \frac{dh}{dt} + 76.36

708 - 76.36 = 30790.75\frac{dh}{dt}

631.64 = 30790.75\frac{dh}{dt}

\frac{dh}{dt}= \frac{631.64}{30790.75}

\frac{dh}{dt} = 0.021 m/min

Hence, the rate of change of the height is 0.021 meters per minute.

3 0
2 years ago
Answer asap 30 points!!!!!!!!!!!!!!!!!!!!!!!!!What is the lateral surface area of the cone?
Ludmilka [50]

Answer:

it would be a

3 0
2 years ago
0.580000 as a fraction
Paul [167]

Answer:

\frac{58}{100}=\frac{29}{50}

Step-by-step explanation:

Since this is mathematics, significant figures are not necessary.  Thus, we can just take 0.58 and delete the 0s.  Now, 0.58=\frac{58}{100}.

6 0
3 years ago
A man invest 5,200,part at 4% and the balance at 3%. If his total income for the two investments is $194,how much money did he i
Fed [463]

Let the amount invested at 4% be = x

Let the amount invested at 3% be = y

Given is:

x+y=5200 or x=5200-y  .... (1)

As, total income for the two investments is $194, so equation is:

0.04x+0.03y=194   ....(2)

Putting value of x from (1) in (2)

0.04(5200-y)+0.03y=194

208-0.04y+0.03y=194

0.01y=14

y=1400

And x=5200-y

x=5200-1400=3800

Hence, money invested at 4% is $3800 and money invested at 3% is $1400

6 0
2 years ago
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