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kvasek [131]
3 years ago
6

Ms. Anderson deposits $700 into a savings account that pays a simple interest of 2% per year. Which of the following would be th

e total amount in her savings account at the end of 10 years?
Mathematics
2 answers:
slavikrds [6]3 years ago
7 0

Answer: 840

Step-by-step explanation:

SI = prt

= 700 x .02 x 10

=140

Amount after 10 years = 700 + 140 = 840

Schach [20]3 years ago
3 0

Answer:

6860

Step-by-step explanation:

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Sorry again I just dont know this.
natta225 [31]

Answer:

7 ; 2 ; 8

Step-by-step explanation:

money for raffle= 350 pounds

money for quiz=14 multiplied by 4= 56

56+44= 100

money for membership fees= 20 multiplied by 20= 400

Ratio

Raffle :Quiz: Membership fees

350 : 100 : 400

35 : 10 : 40 (divided by 10)

7 : 2 : 8        (divided by 5)

it can not be simplified further

4 0
3 years ago
A serving of chickpeas contains 2,150 milligrams of potassium. How many grams of
Zepler [3.9K]

Answer: 109 mg

Step-by-step explanation:

5 0
2 years ago
Which point on the number line represents the number that can be added to-3
vova2212 [387]

Answer: 3

Step-by-step explanation: This is because the 2 numbers are opposites, which cancel each other out, going back to zero.

8 0
3 years ago
Read 2 more answers
X + 3 =12 <br><br>What Number Is X<br><br>​
gulaghasi [49]
The answer is 9, to find it just do inverse and in this case that is 12-3 and u should always get the answer
7 0
3 years ago
Read 2 more answers
            Find the approximate solution of this system of equations.
Montano1993 [528]
Y = |x² - 3x + 1|
y = x - 1

|x² - 3x + 1| = x - 1
|x² - 3x + 1| = ±1(x - 1)
|x² - 3x + 1| = 1(x - 1)       or      |x² - 3x + 1| = -1(x - 1)
|x² - 3x + 1| = 1(x) - 1(1)    or    |x² - 3x + 1| = -1(x) + 1(1)
|x² - 3x + 1| = x - 1        or         |x² - 3x + 1| = -x + 1
  x² - 3x + 1 = x - 1         or          x² - 3x + 1 = -x + 1
        - x        - x                                + x         + x
  x² - 4x + 1 = -1           or            x² - 2x + 1 = 1
              + 1 + 1                                       - 1 - 1
  x² - 4x + 1 = 0              or           x² - 2x + 0 = 0
  x = -(-4) ± √((-4)² - 4(1)(1))    or    x = -(-2) ± √((-2)² - 4(1)(0))
                      2(1)                                             2(1)
  x = 4 ± √(16 - 4)            or            x = 2 ± √(4 - 0)
                 2                                                 2
  x = 4 ± √(12)              or               x = 2 ± √(4)
             2                                                  2
 x = 4 ± 2√(3)               or               x = 2 ± 2
             2                                                2
 x = 2 ± √(3)                or                x = 1 ± 1
 x = 2 + √(3)  or  x = 2 - √(3)   or    x = 1 + 1    or    x = 1 - 1
                                                      x = 2       or       x = 0
y = x - 1          or           y = x - 1                            or    y = x - 1   or    y = x - 1
y = (2 + √(3)) - 1    or    y = (2 - √(3)) - 1          or         y = 2 - 1    or    y = 0 - 1
y = 2 - 1 + √(3)     or      y = 2 - 1 - √(3)          or           y = 1      or       y = -1
y = 1 + √(3)        or        y = 1 - √(3)               (x, y) = (2, 1)    or    (x, y) = (0, -1)
       (x, y) = (2 ± √(3), 1 ± √(3))

The solution (0, -1) can be made by one function (y = x - 1) while the solution (2 ± √(3), 1 ± √(3)) can be made by another function (y = |x² - 3x + 1|). So the solution (2, 1) can be made by both functions, making the two solutions equal.
4 0
3 years ago
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