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Taya2010 [7]
3 years ago
12

You want to estimate the number of students in a junior high school who ride the school bus. Which sample is unbiased? PLEASE HE

LP!!!​

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0
I would say C. This is because these students are the first 50 who are on the roster & has nothing to do with either side.
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PLZ HELP ASAP AND SHOW UR WORK!!!! THE ≤. WITHOUT THE LINE IN THE BOTTOM
Marina86 [1]

Answer:

B

Step-by-step explanation:

\frac{2}{3}x +6

subtract 6 from both sides

\frac{2}{3}x

divide by 2/3(or multiply by 3/2)

x

and thats your answer

3 0
3 years ago
What is the strongest relationship you can infer between two variables from this statement? The number of minutes you can talk o
Elenna [48]
It wokls be b. I hope this helps
4 0
2 years ago
If 50-3x=x-26, then x=
IgorLugansk [536]

Answer:

x=19

Step-by-step explanation:

50 - 3x = x -26

50-3x-50=x-26-50

-3x=x-76

-3x-x=x-76-x

-4x= -76

x= -76/-4

x=19

6 0
3 years ago
Two cars start at the same point. One travels north at 65 km/h and the other travels east at 50 km/h. How far are they apart aft
Naya [18.7K]

Answer:

1they are 15 kilometers apart

7 0
3 years ago
1. & 2. In the diagram below, points A, B, and C are collinear. Answer each of the following questions. The figure shown bel
Lana71 [14]

Answer:

a)  \overline{AB} = 8 in

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. \overline{AB} = 10 in

c)  When the length of AB = 10.2 in. and BC = 3.7 in.  \overline {AC}  = 6.5 in

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. \overline {BC} =  1\frac{1}{2} in

Step-by-step explanation:

a) When the length of AC = 5 in. and CB = 3 in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 5 in. + 3 in. = 8 in.

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 6\frac{1}{2} in.+ 3\frac{1}{2} in. = 10 in.

c) When the length of AB = 10.2 in. and BC = 3.7 in. we have;

The length of \overline {AC} = AB - BC (converse of the segment addition postulate)

Therefore;

\overline {AC} = 10.2 in.+ 3.7 in. = 6.5 in.

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. we have;

The length of \overline {BC} = AB - AC (converse of the segment addition postulate)

Therefore;

\overline {BC} = 4\frac{3}{4} in. -  3\frac{1}{4} in.=  1\frac{1}{2} in.

6 0
3 years ago
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