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3 years ago

Find the mean median mode and range 2,5,9,4,3

2 answers:

3 0

Mean: 4.6 (basically the average
Median: 4 (the number in the middle
Mode: there isn’t one (it’s the number repeated the most)
Range: 7 (largest and smallest number subtracted

timurjin [86]3 years ago

3 0

list the following data set from least to greatest:

2, 3, 4, 5, 9

range: highest value - lowest value = answer

Range: 9 - 2 = 7

Mode: there is no mode in this data set, (mode represents how many times a number is repeated)

(for example: 2, 5, 5, 6, 14, the following mode in this data set is 5)

Mode: none

mean:

(just add up all the numbers and divide it by 5 since there are 5 numbers in the following data set, or the listed numbers.)

2 + 5 + 9 + 4 + 3 = 23/5 = 4.6

mean: 4.6

range: 7

Mode: None, there are no mode in the data set or listed numbers.

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The length of a rectangle is 3 meters less than 3 times the width. the perimeter is 58 meters. find the width.

diamong [38]

If I'm correct 40.5 meters

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3 years ago

The equation y = 0.035x shows the relationship between the grams and ounces.

scoundrel [369]

The equation y = 0.035x where x is in grams, and y is ounces, then 22 grams would be 0.035 x 22 = 0.77 ounces

4 0

3 years ago

Please any help is necessary

Ugo [173]

Answer:

Option D. 50 ft

Step-by-step explanation:

we know that

The area of the figure is equal to the area of three rectangles

$A=18x+(48-36)(32-11)+(18)(32)$

$A=18x+(12)(21)+(18)(32)\\A=18x+828$

Remember that the area is given

$A= 1,728\ ft^2$

$18x+828=1,728$

solve for x

$18x=1,728-828\\18x=900\\x=50\ ft$

3 0

3 years ago

I need some help with this question

yarga [219]

Answer:

-7/15

Step-by-step explanation:

-4/5 translates to -12/15 and 1/3 translates to 5/15.

When you add -12/15+5/15 you get

-12+5/15 so you get -7/15

5 0

3 years ago

Suppose a certain manufacturing company produces connecting rods for 4- and 6-cylinder automobile engines using the same product

gregori [183]

Answer:

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

Step-by-step explanation:

The cost for the four cylinder production line is $C_4 = \$2,100$

The cost for the six cylinder production line is $C_6 = \$3,500$

The manufacturing cost for each four cylinder is $M_4= \$13$

The manufacturing cost for each six cylinder is $M_6= \$16$

The weekly production capacity for 4 cylinder connecting rod is $W_4 = 5,000$

The weekly production capacity for 6 cylinder connecting rod is $W_6 = 8,000$

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

3 0

3 years ago