Givn : OK = 3, OJ = 30, KN = 1, JM = 3
ON=OK+KN=3+1=4
OM=OJ+JM=30+10=40
In triangles OKJ & ONM,
OKOJ=330=110
ONOM=440=110
Angle O is common in both the triangles.
Two sides are in same proportion and the included angle is common (SAS) . Hence both the triangles are similar.
That means KJNM=110 or the two sides are parallel.
Hence ˆK=ˆN,ˆJ=ˆM corresponding angles.
Make a line down the other side of the E so it becomes a rectangle, find the area of the big rectangle (12•10=120 inches) then find the smaller rectangles (7•5=35 inches) since there’s two small rectangles w the same measurements the area is the same(35+35= 70 inches) , Now u wanna subtract the area of the two small rectangles ( 70-120=50 inches) the Area of the E is 50 inches
Hope I explain it okay and it helps you!
Answer:
What in XXXtarnation!! Got to be my favorite ngl
I would say C because when looking at the y-values, 1/2 x 2 = 1, 1 x 2 = 2, and 1 x 2 = 4. I hope this helps a bit!!
For this problem, you haven = 360p = 1/6q = 5/6 E[x] = np = 360*1/6 = 60SD[x] = √(npq) = √(360*1/6*5/6) = √(50) ≈ 7.07
