X is equal to 2. put 2 in for X and try to solve it
Answer
Length measured using Ruler A= 1.17 dm
Length measured using Ruler B=1.18 dm
Step by Step Explanation:
I have added the missing photograph which shows the length of pencil being measured with two rulers.
Ruler A has marking separated by 1 dm
Ruler B has marking separated by 0.1 dm
Length measured using Ruler A= 1.17 dm
(As we can see I have added the middle markers, we can see the tip of pencil is somewhere between 1 and 1.25, it is more than 1.125 but lesser than 1.25, it is somewhere around 1.2 and 1.125 dm, approximately equal to one half of 1.25 which is 1.125 with addition of one of the three halves of half of 1.125 which is 1.125+0.045 dm hence 1.17dm)
Length measured using Ruler B=1.18 dm
(we can see the tip of pencil is just before 1.2 dm, it is clear that the value is precisely 1.18 and not 1.19 dm)
<u><em>Tip:Always measure one more decimal than given by the ruler when unsure about the exact value</em></u>
Terminating because the decimal ends rather than going on forever which would be repeating
Given:
First term of an arithmetic sequence is 2.
Sum of first 15 terms = 292.5
To find:
The common difference.
Solution:
We have,
First term: 
Sum of first 15 terms: 
The formula of sum of first n terms of an AP is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where, a is first term and d is common difference.
Putting
, n=15 and a=2 in the above formula, we get
![292.5=\dfrac{15}{2}[2(2)+(15-1)d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B2%282%29%2B%2815-1%29d%5D)
![292.5=\dfrac{15}{2}[4+14d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B4%2B14d%5D)
![292.5=15[2+7d]](https://tex.z-dn.net/?f=292.5%3D15%5B2%2B7d%5D)
Divide both sides by 15.




Dividing both sides by 7, we get


Therefore, the common difference is 2.5.
Answer:
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