In a normal distribution, what is the probability that a data value will fall below the
1 answer:
Answer:
A 99.96%
Step-by-step explanation:
The z score shows by how many standard deviations the raw score is above or below the mean. The z score is positive if the raw score is above the mean while the z score is negative if the raw score is below the mean. The z score is given by:
The probability can be gotten from the normal distribution table. Therefore from the normal table:
P(z < 3.37) = 0.9996 = 99.96%
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Answer:
The statements about arcs and angles that are true in the figure are;
1) ∠EFD ≅ ∠EGD
2)
3) mFD = 120°
Step-by-step explanation:
1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)
∠CEG = ∠CDG = 90° (Given)
∠GDE = 60° (Given)
∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)
∠ECD = 360° - (90° + 90° + 60°) = 120°
∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)
120° = 2 × ∠EFD
∠EFD = 120°/2 = 60°
∠EFD ≅ ∠EGD
∠ECD = 120°
∠EGD = 60°
∴∠EGD ≠ ∠ECD
2) Given that arc mEF ≅ arc mFD
Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF
∠ECF = mEF = mFD = ∠DCF (Given)
∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)
(Corresponding Parts of Congruent Triangles are Congruent, CPCTC)
∠FED ≅ ∠FDE (base angles of isosceles triangle)
∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)
∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°
∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)
2 × ∠FED = 120°
∠FED = 120°/2 = 60° = ∠FDE
∴ ∠FED = ∠FDE = ∠EFD = 60°
ΔEFD is an equilateral triangle as all interior angles are equal
(definition of equilateral triangle)
3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)
Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)
60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)
60° = 2 × ∠CFE
∠CFE =60°/2 = 30° = ∠CFD
(radii of the same circle)
ΔFCD is an isosceles triangle (definition)
∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)
∠CFD + ∠CDF + ∠DCF = 180°
∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°
mFD = ∠DCF (definition)
mFD = 120°.
From the given dimensions, of MI, IN, NT, TM, and MN, the quadrilateral
MINT can be drawn as shown in the attached image.
<h3>What are the steps for the construction of MINT?</h3>The given dimensions of the quadrilateral MINT are;
MI = 5 cm
IN = 6 cm
NT = 7 cm
TM = 3 cm
MN = 9 cm
The side MN is a diagonal of MINT, therefore;
ΔMIN, and ΔMTN are triangles with a common base = MN
The steps to construct MINT are therefore;
- Step 1; Draw the line MN = 9 cm.
- Step 2; Place the compass at point <em>M</em> and with a radius MI = 5 cm, draw an arc on one side of MN.
- Step 3; Place the compass at <em>N</em> and with radius IN = 6 cm, draw an arc to intersect the arc dawn in step 1 above.
- Step 4; Place an arc at point <em>M</em> and with radius TM = 3 cm draw an arc on the other side of MN.
- Step 5; Place the compass at point <em>N</em> and with radius NT = 7 cm, draw an arc to intersect the arc drawn in step 3.
- Step 6; Join the point of intersection of the arcs to points <em>M</em> and <em>N</em> to complete the quadrilateral MINT.
Please find attached the drawing (showing the construction arcs) of the
quadrilateral MINT created with MS Word.
Learn more about types of geometric construction here:
