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3 years ago

Shannon's net worth is $872. 17 and her liabilities are $15,997.

Mathematics

2 answers:

saul85 [17]3 years ago

6 0

Answer:

I think it should be b

Step-by-step explanation:

B is the answer I think

ira [324]3 years ago

4 0

Answer:

I think it's b too.

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Determine where the real zeros of f(x) = x4 - 2x3 + x - 2 are located.

Digiron [165]

Step-by-step explanation:

Step 1: Factor by grouping

$x^4 - 2x^3 + x - 2$

$x^3(x - 2) + 1(x - 2)$

$(x^3 + 1)(x - 2)$

Step 2: Solve for x

$x^3 + 1 = 0$

$x^3 = -1$

$\sqrt[3]{x^3} = \sqrt[3]{-1}$

$x = -1$

$x - 2 = 0$

$x - 2 + 2= 0 + 2$

$x = 2$

Answer: $Option\ A, \ at\ -1 \ \& \ 2$

4 0

3 years ago

Read 2 more answers

Simplify 3(2x^4*y^5)^2/(6x^3*y^3)^6

Thepotemich [5.8K]

$\dfrac{3(2x^4y^5)^2}{(6x^3y^3)^6}\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=\dfrac{3(2^2)(x^4)^2(y^5)^2}{6^6(x^3)^6(y^3)^6}=\dfrac{3(4)x^8y^{10}}{46656x^{18}y^{18}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{12x^8y^{10}}{46656x^8x^{10}y^{10}y^8}=\dfrac{1}{3888x^{10}y^8}$

7 0

4 years ago

Which of the following expressions are equivalent to

Alexus [3.1K]

Answer:

$(2^{6})^{\frac{1}{2} } , 4^{\frac{1}{2} } * 16^{\frac{1}{2} },8^{\frac{1}{2} } * 8^{\frac{1}{2}, \sqrt{16*4}$

Step-by-step explanation:

Some facts to establish before we try to solve: $\sqrt{64} =8$ and another way of writing $\sqrt{64}$ is $64^{\frac{1}{2} }$ . Also order of operations: PEMDAS

For the first option:

We solve what is in the parenthesis: 2*2=4*2=8*2=16*2=32*2=64 so $64^{\frac{1}{2} }$ , which is another way to write $\sqrt{64}$

For the second option: If the square root of 64 is 8, the there is no way we can multiply another value by it.

The third option: When dealing with square roots, we can solve the inside first and then take the square root:

$8^{2} *8^{2} = 64 * 64=$ definitely not 64 (though if you're curious it's 4096)

The fourth: Another way to write the square root is to raise the value to the 1/2 power so

$4^{\frac{1}{2} }* 16^{\frac{1}{2} }= \sqrt{4} *\sqrt{16} = 2*4=8$

Which is the same as $\sqrt{64}$

Fifth: Like the third, we solve the inside of the square root first

16*4= 64 and then $\sqrt{64}$

Sixth: We need a nice whole number (8), and $\sqrt{32}$ has no clean roots, so its result will have decimals. It can't be our answer

7 0

3 years ago

Write equation The quotient of x and z is y

siniylev [52]

XYZ ABC XYZ ABC have a nice day

6 0

4 years ago

Fnd the missng side length

mixas84 [53]

Answer:

18m?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers