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True [87]
3 years ago
13

Veronica is buying cubed cheese from Mr.Sands deli.she asks for 1 3/4 pounds. When Mr.Sand places some cheese in a container and

weighs it,the scale shows 1 1/4 pounds. The container weighs 1/16 pounds. How many more pounds of cheese would Mr.Sand need to add to the scale to get the amount that Veronica asked for? Explain how you solved the problem.
Mathematics
1 answer:
nirvana33 [79]3 years ago
3 0
Amount of cubed cheeses that Veronica wants to buy =1 3/4 pounds

=7/8 pounds
Weight of the container in which Mr. Sand places the cube =1/16 pounds 
Weight of the cubed cheese and container together =1 1/4 pounds 
=5/4 pounds 
Then the amount of cubed cheese placed by Mr.Sands =(5/4-1/16) pounds
=(20-1)/16 pounds 
=19/16 pounds
So the quanity of more cheese that Mr.Sands need to add to the scale =(7/4-19/16)pounds
=(28-19)/16pounds 
From the above debuction we can easily conclude that Mr.Sand need to add 9/16pounds of cubed cheese to fullfil the order placed by Veronica
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Find a possible formula for a fourth degree polynomial g that has a double zero at -2, g(4) = 0, g(3) = 0, and g(0) = 12. g(x) =
astraxan [27]
<h2>Answer:</h2>

The possible formula for a fourth degree polynomial g is:

         g(x)=\dfrac{1}{4}(x^4-3x^3-12x^2+20x+48)

<h2>Step-by-step explanation:</h2>

We know that if a polynomial has zeros as a,b,c and d then the possible polynomial form is given by:

f(x)=m(x-a)(x-b)(x-c)(x-d)

Here the polynomial g  has a double zero at -2, g(4) = 0, g(3) = 0.

This means that the polynomial g(x) is given by:

g(x)=m(x-(-2))^2(x-4)(x-3)\\\\i.e.\\\\g(x)=m(x+2)^2(x-4)(x-3)\\\\i.e.\\\\g(x)=m(x^2+2^2+2\times 2\times x)(x(x-3)-4(x-3))\\\\i.e.\\\\g(x)=m(x^2+4+4x)(x^2-3x-4x+12)\\\\i.e.\\\\g(x)=m(x^2+4+4x)(x^2-7x+12)\\\\i.e.\\\\g(x)=m[x^2(x^2-7x+12)+4(x^2-7x+12)+4x(x^2-7x+12)]\\\\i.e.\\\\g(x)=m[x^4-7x^3+12x^2+4x^2-28x+48+4x^3-28x^2+48x]\\\\i.e.\\\\g(x)=m[x^4-7x^3+4x^3+12x^2+4x^2-28x^2-28x+48x+48]\\\\i.e.\\\\g(x)=m[x^4-3x^3-12x^2+20x+48]

Also,

g(0)=12

i.e.

48m=12\\\\i.e.\\\\m=\dfrac{12}{48}\\\\i.e.\\\\m=\dfrac{1}{4}

Hence, the polynomial g(x) is given by:

g(x)=\dfrac{1}{4}(x^4-3x^3-12x^2+20x+48)

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