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2 years ago

What is the estimate of 95×17

Mathematics

2 answers:

rusak2 [61]2 years ago

8 0

The estimate is 1,615

koban [17]2 years ago

7 0

1615
95 * 17 = 1,615
Calculators make it easier be sure to have one.

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I'm new to this math and it's very confusing it's asking that Fill out the Venn diagram using the given information.

GREYUIT [131]

There are the answers filled in :)

5 0

1 year ago

PLEASE HELP ASAP PSLLLSLSL look at photo

shtirl [24]

Answer:

Last one

Step-by-step explanation:

Negative one times 6r is -6r and then that eliminates two of the four. the rest is common sense tbh.... but it is the last one. Hope this helps

3 0

2 years ago

How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l

musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - α) % confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The margin of error in this interval is:

$MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The formula to compute the sample size is:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}$

(1)

Given:

$\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97$

Thus, the minimum sample size required is 97.

(2)

Given:

$\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385$

Thus, the minimum sample size required is 385.

(3)

Given:

$\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604$

Thus, the minimum sample size required is 9604.

8 0

2 years ago

A print shop prints 356 copies of a booklet. The booklet has 38 pages. How many pages were printed?

FrozenT [24]

Answer:

13528 pages

Step-by-step explanation:

356 x 38= 13528

4 0

2 years ago

In the figure, j || k and m<1 = 63º.

Aleonysh [2.5K]

Answer: m<4 = 117 degrees

Step-by-step explanation:

Knowing that angle 1 is 63 degrees, we can look at the other angle on the same side of the line, angle 4.

Angles on one side of a line add to 180 degrees.

180 - 63 = 117

7 0

2 years ago