All categories

3 years ago

2[2y-1]+5=19 what are the solutions?

Mathematics

2 answers:

Vika [28.1K]3 years ago

8 0

Answer:

The answer to your question is y = 4

Step-by-step explanation:

2(2y - 1) + 5 = 19

Subtract 5 in both sides

2(2y - 1) + 5 - 5 = 19 - 5

Simplify

2(2y - 1) = 14

Divide both sides by 2

2(2y - 1)/2 = 14/2

Simplify

2y - 1 = 7

Add 1 to both sides

2y - 1 + 1 = 7 + 1

Simplify

2y = 8

Divide by 2 both sides

2y/2 = 8/2

Simplify

y = 4

skelet666 [1.2K]3 years ago

5 0

Answer:

y = 4

Step-by-step explanation:

2[2y-1]+5=19 (by PEDMAS, distribute parentheses first)

(2)(2y) - (2)(1) + 5 = 19

4y - 2 + 5 = 19

4y +3 = 19 (subtract 3 from both sides)

4y = 19 - 3

4y = 16 (divide both sides by 4)

y = 16/4

y = 4

You might be interested in

HELP I NEED THE ANSWERS FOR ALL OF THESE QUESTIONS!

inysia [295]

11. 38*
14. 1808,64m3
13. 5/3ft
i cant figure out the two left

7 0

3 years ago

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0

2 years ago

1. **Which of the foll byowing is equivalent to y4 x y^8?

andrey2020 [161]

Answer:

<h2>SOLUTION</h2>

${y}^{4} \times {y}^{8} = y8 + 4 = {y}^{12}$

<h3>Beacause of the property of exponent = </h3><h3> $a ^{b} \times {a}^{c} = a ^{b + c}$ </h3>

8 0

3 years ago

In what order must you preform the operations indicated by a negative rational exponent?

Svet_ta [14]

The operations referred to are likely

• raising to a power (the numerator of the exponent)

• taking a root (the denominator of the exponent)

• finding a reciprocal (because the exponent is negative)

They can be performed in any convenient order. It often works well to deal with small positive integers, so if one or more of these operations lets you proceed with a small positive integer for the remaining operations, that would be the one you'd perform first.

_____

A computer performing operations with a negative rational exponent may do so using logarithms. That is, the log of the base will be multiplied by the exponent, then the antilog found. The exponent itself will likely be treated as a floating point number, unless coding specifically indicates otherwise.

4 0

3 years ago

a positive integer is nice if there is a positive integer with exactly four positive divisors (including and ) such that the sum

antoniya [11.8K]

Answer:

A positive integer with exactly four positive divisors (including and ) such that the sum of the four divisors is equal to The sum of four divisors is equal to 45360.

What is an integer?

Zero, a positive natural number, or an unsigned negative integer are all examples of integers. The inverses of the equivalent positive numbers, which are additive, are the negative numbers. The boldface Z or blackboard bold "Z" is frequently used in mathematical notation to represent a collection of numbers.

Step-by-step explanation:

We know That total No. of factors

=product of (prime no′s power+1)

If N is the number of different divisors:

N=(p1+1)⋅(p2+1)⋅⋅⋅(pn+1)

100= 2^2 × 5^2

=2×2×5×5= (1+1)(1+1)(4+1)(4+1)

Then the integer n= a1^p1⋅a2^p2⋅⋅⋅⋅an^pn

For the smallest value: p1=4,p2=4,p3=1,p4=1

Then,

n=a1^4×a2^4×a3^1×a4^1

=24⋅34⋅51⋅71

=16⋅81⋅5⋅7

=45360

Hence, the positive integer with exactly four positive divisors (including and ) such that the sum of the four divisors is equal to The sum of four divisors is equal to 45360.

To learn more about the integers from the given link

brainly.com/question/929808

#SPJ4

4 0

1 year ago