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GaryK [48]
4 years ago
14

Please help please help

Mathematics
1 answer:
Sindrei [870]4 years ago
7 0

Answer:

(-2,2)

Step-by-step explanation:

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Yes that is correct because 4-3 plus 5 is 6 and -6 +8+4 is 6 soo dont stress your self out..Lol
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Find the length of the function over the given interval. y = 3x from x = 0 to x = 2
olganol [36]

The length of the function y = 3x over the given interval [0, 2] is 3.2 units

For given question,

We have been given a function  y = 3x

We need to find the length of the function on the interval x = 0 to x = 2.

Let f(x) = 3x where f(x) = y

We have  f'(x) = 3,  so  [f'(x)]² = 9.  

Then the arc length is given by,

\int\limits^a_b {\sqrt{1+[f'(x)]^2} } \, dx\\\\= \int\limits^2_0 {\sqrt{1+9} }\, dx\\\\=\sqrt{10}\\\\ =3.2

This means, the arc length is 3.2 units.

Therefore, the length of the function y = 3x over the given interval [0, 2] is 3.2 units

Learn more about the arc length here:

brainly.com/question/10729208

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2 years ago
Which is the same as multiplying a number by two?
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C adding a number to itself 
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4 years ago
Himpunan penyelesaian pertidaksamaan nilai mutlak |2x-4| > |3x+2|
Stells [14]

Answer:

The solution in interval notation is:

(-6,\frac{2}{5}).

The solution in inequality notation is:

-6.

Step-by-step explanation:

I think you are asking how to solve this for x.

Keep in mind |x|=\sqrt{x^2}.

|2x-4|>|3x+2|

\sqrt{(2x-4)^2}>\sqrt{(3x+2)^2}

If \sqrt{u}>\sqrt{v} then u>v.

(2x-4)^2>(3x+2)^2

Subtract (2x-4)^2 on both sides:

0>(3x+2)^2-(2x-4)^2

Factor the difference of squares a^2-b^2=(a-b)(a+b):

0>((3x+2)-(2x-4))((3x+2)+(2x-4))

Simplify inside the factors:

0>(x+6)(5x-2)

(x+6)(5x-2)

The left hand side is a parabola that faces up.  I know this because the degree is 2.  

The zeros of the the parabola are at x=-6 and x=2/5.

We can solve x+6=0 and 5x-2=0 to reach that conclusion.

x+6=0

Subtract 6 on both sides:

x=-6

5x-2=0

Add 2 on both sides:

5x=2

Divide both sides by 5:

x=2/5

Since the parabola faces us and (x+6)(5x-2) then we are looking at the interval from x=-6 to x=2/5 as our solution.  That part is where the parabola is below the x-axis.  We are looking for where it is below since it says the where is the parabola<0.

The solution in interval notation is:

(-6,\frac{2}{5}).

The solution in inequality notation is:

-6.

6 0
4 years ago
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