Please help this is confusing me:(
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Answer:
I am attaching a image to understand my proof.
Step-by-step explanation:
PROVE:-
AB = DC
AD = BC
∠ ABD = ∠ BDC (alternate angles are equal )
∠ DBC = ∠ ADB (alternate angles are equal )
∴ Δ ADB ≅ Δ CBD ( by ASA rule )
DC = BA ( corresponding sides of ≅ Δ )
AD = CB ( corresponding sides of ≅ Δ )
Hence it is proved that opposite sides of parallelogram are congruent )
