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3 years ago

Please help this is confusing me:(

Mathematics

1 answer:

nirvana33 [79]3 years ago

3 0

Answer :
-8 miles per min
He travels 3.25min

-8 x 3.5= -26

He traveled 26 miles in 3.25

I hope this helped

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Help me i’ll give extra points

vekshin1

they are moving on a moving object

if they went onward with the bus going forward, they would go mph faster;

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3 years ago

You are ordering T-shirt with your school's mascot printed on them. Each T-shirt cost $4.75. The printer charges a setup fee of

masya89 [10]

Answer:

1. n(4.75+30+2.50)

2. 4.75n+30n+2.50n

Step-by-step explanation:

n is the number of shirts they buy. It says that each shirt costs $4.75, and for each shirt they add an extra $30 and $2.50 for the setup fee and to peint each shirt. The word each shows that you have to times. You have to times n by each number or to make it shorter put all three numbers in parenthesis put the n ouside of the parenthesis.

Hope that helps.

4 0

3 years ago

Read 2 more answers

134 A financial analyst believes that if interest rates decrease in a given period then the

lawyer [7]

The probability that the market will go up and interest rate will go down during the period in question is 0.03.

<h3>What is the probability?</h3>

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability that the market will go up and interest rate will go down = 0.08 X 0.40 = 0.03

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

5 0

2 years ago

How do i solve this? Please give me step by step explanation.

Viktor [21]

Answer:1.5

Step-by-step explanation:

12.6j + 8 = 10.2j +4.4

2.4j=3.6

j=3.6/2.4= 1.5

3 0

3 years ago

Read 2 more answers

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

4 0

3 years ago