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Westkost [7]
3 years ago
7

You are starting a new business in which you have decided to sell two products instead of just one. Determine a business you cou

ld start and choose two products that you could sell. How much of your own money are you willing to invest in this business in order to get started? How much will each item cost you to make? How much will you charge for each item?
Mathematics
1 answer:
svp [43]3 years ago
5 0

If I had to choose a business to start off with I would start a lemonade stand With cookies

First let's do the lemonade Side Let's say I put $100 into the business And it cost a dollar per lemon $5 for 10 lb of sugar It takes about five lemons about and  a pound of sugar to make one batch  that makes about 20 cups of Lemonade Each cup of lemonade for cost me roughly $0.50 I would then sell Each cup of lemonade for $0.75 and make a 5 profit Now let's talk about the cookie portion of the business You have to get milk flour sugar and salt Together that cost maybe $10 per batch Of 50 cookies Which cost roughly $0.20 to Make You can sell them at with a profit of $0.05 for $0.25 After $25 Prophet.So overall you will make roughly $30

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Felix says if 2/3 pan of lasagna had been left over from dinner and the padis family ate 1/2 of that for lunch, the answer would
olga_2 [115]

Answer:

He is right he can eat 2/6 f the whole pan of lasagna

Step-by-step explanation:

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2/6 is half of the total pan of lasagna, padis family ate half of 2/3 wich is 2/6 and left 2/6 for Felix

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3 years ago
What 5.871 5.781 is equal or lest or greater
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7 0
3 years ago
Read 2 more answers
You have 12 1/3 yards and you need 47 yards how many more yards of fabric do you need
Lady bird [3.3K]

Answer:

34 2/3

Step-by-step explanation:

You need 47 yards. You have 12 1/3

47 - 12 1/3. So we'll break it down.

47 - 12 = 35.

Now, 35 + 12 1/3 would make 47 1/3

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4 0
3 years ago
P= $790, t= 3, r=4% compounded continuously : Find A
Savatey [412]
\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$790\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to &3
\end{cases}
\\\\\\
A=790e^{0.04\cdot 3}\implies A=790e^{0.12}
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3 years ago
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