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german
3 years ago
15

Kalsom answers 25 questions in math tests. He scored 81% to 93%. Calculate all possible number of questions successfully answere

d by Kalsom. How to solve it.​
Mathematics
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

21 and 22

Step-by-step explanation:

Let's work backward from that 81%:  x/25 = 0.81 yields x = 20.25.  Nominally, 20.25 / 25 = 0.81, but x must be an integer.  Let's round 20.25 off to 20.

Thus, if Kalsom got 81%, it was a result of his having done 20 questions correctly.

81% corresponds to 20 questions correct;

82% to 20.5 questions correct, or, rounding up, to 21 questions correct;

83% to 20.75, or 21;

84% to 21 questions correct; this is the only result that makes sense (whole number of questions answered correctly)

85% to 21.25;

86% to 21.5;

87% to 21.75;

88% to 22 questions correct (this makes sense, unlike the last three)

89% to 22.25;

90% to 22.5;

91% to 22.75;

Assuming that the number of questions correct MUST be integer, then the possible number correct are 21 and 22, corresponding to 84% and 88% respectively.

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Step-by-step explanation:

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3 years ago
What is the value of the expression f(-3) + 2f(-1) - f (4)<br><br> PLEASE HELP NO LINKS
Bas_tet [7]

Answer:

22

Step-by-step explanation:

Find f(-3) :

f(x) = x² + 2x for x ≤ -3

That means for those values of x, less than or equal to -3, this is the function.

So, f(-3) = (-3)² + 2(-3) = 9 - 6 = 3

Now, f(-1) :

From the given data, we see it is: f(x) = 2 (\frac{1}{3} )^{2x}

We take this because -1 lies between -3 and 4.

Now, f(-1) = 2 (\frac{1}{3} )^{2(-1)}

 => f = (-1) = 2(3)^{2} = 2 (9) = 18

For f(4) :

Clearly, the function is: f (x) = \frac{2x - 5}{x-7}

f (4) = \frac{2(4)-5}{4-7} = \frac{3}{-3} = -1

Therefore, <u>f(-3) + f(-1) - f(4) = 3 + 18 - (-1) = 3 + 18 + 1 = 22.</u>

5 0
3 years ago
If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal
lorasvet [3.4K]

Answer:

a

   The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

b

   The probability is  P(Z >  2.5 ) =  0.0062097

Step-by-step explanation:

From the question we are told that

        The  population mean is  \mu =  800

        The  variance is  var(x) =  1600 \ kg

        The  range consider is  x_1 =  778 \ kg  \  x_2 =  834 \ kg

         The  value consider in second question is  x =  900 \ kg

Generally the standard deviation is mathematically represented as

        \sigma =  \sqrt{var (x)}

substituting value

        \sigma =  \sqrt{1600}

       \sigma = 40

The percentage of a cucumber give the crop amount between 778 and 834 kg  is mathematically represented as

       P(x_1 <  X <  x_2 ) =  P( \frac{x_1 -  \mu }{\sigma} <  \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma }   )

    Generally  \frac{X - \mu }{ \sigma } = Z (standardized \  value  \  of  \  X)

So

      P(x_1 <  X <  x_2 ) =  P( \frac{778 -  800 }{40} < Z< \frac{834 - 800 }{40 }   )

      P(x_1 <  X <  x_2 ) =  P(z_2 < 0.85) -  P(z_1 <  -0.55)

From the z-table  the value for  P(z_1 <  0.85) =  0.80234

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So

             P(x_1 <  X <  x_2 ) =   0.80234 - 0.29116

             P(x_1 <  X <  x_2 ) =   0.51118

The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

             P(X > x ) =  P(\frac{X - \mu }{\sigma }  > \frac{x - \mu }{\sigma } )

substituting values

             P(X > x ) =  P( \frac{X - \mu }{\sigma }  >\frac{900 - 800 }{40 }   )

             P(X > x ) =  P(Z >2.5   )

From the z-table  the value for  P(Z >  2.5 ) =  0.0062097

 

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2 years ago
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