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3 years ago

Help identify the volume!

Mathematics

2 answers:

valkas [14]3 years ago

6 0

You multiply all the numbers to get your answer will be 172,800cm I hope that right

Romashka [77]3 years ago

3 0

Volume equals length times width

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4x + 7 = 23slove this

Juli2301 [7.4K]

Given:

4x + 7 = 23

Let's solve for x.

First Step:

Subtract 7 from both sides

4x + 7 - 7 = 23 - 7

4x = 16

Next Step:

DIvide both sides by 4

$\begin{gathered} \frac{4x}{4}=\frac{16}{4} \\ \\ x\text{ = 4} \end{gathered}$

ANSWER:

x = 4

4 0

1 year ago

What is the domain of the graph ?

marysya [2.9K]

The domain of the graph is all real numbers because the value doesn’t have an end point.

3 0

3 years ago

Solve for X<br><br> PLEASE HELP ME

guapka [62]

Answer:

x = 10°

Step-by-step explanation:

Step 1:

92° + x° + 78° = 180° Supplementary Angles

Step 2:

x° + 170° = 180° Combine Like Terms

Step 3:

x° = 180° - 170° Subtract 170° on both sides

Answer:

x = 10°

Hope This Helps :)

4 0

3 years ago

Add. 7/4+9/-5 wrote your answer as a fraction in simplest form

IgorLugansk [536]

Answer:

7/4 + 9/-5 =

Since the denominator of the second fraction is negative the sign will change from negative to positive

We will get

7/4 - 9/5

First find the LCM

LCM of 4 and 5 is 20

7/4 - 9/5 = 5(7) - 4(9)/ 20

Simplify

We get

35 - 36/20

= -1/20

Hope this helps

5 0

3 years ago

Read 2 more answers

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

4 years ago