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2 years ago

What is the solution set of x for the given equation? x^2/3=x^1/3+4=6 A. -2, -1 B. 2, -1 C. -8, -1 D. 8, -1 E. 2, 8

Mathematics

1 answer:

Valentin [98]2 years ago

3 0

Answer:

Interpreting as: x^2/3=x^1/3+4=6 A

Input:

x^2/3 = x^(1/3) + 4 = 6 A

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An airplane on autopilot took 5 hours to travel 3,475 kilometers, what is the unit rate?

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Km/h kilometre per hour

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2 years ago

The owner of two hotels is ordering towels. He bought 84 hand towels and 22 bath towels for his hotel in Milford, spending a tot

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2 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten

Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

$Q(t) = Q(0)e^{-rt}$

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that $Q(12) = 0.5Q(0)$

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-12r}$

$e^{-12r} = 0.5$

$\ln{e^{-12r}} = \ln{0.5}$

$-12r = \ln{0.5}$

$12r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{12}$

$r = 0.05776$

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

$Q(t) = Q(0)e^{-rt}$

$50 = 200e^{-0.05776t}$

$e^{-0.05776t} = 0.25$

$\ln{e^{-0.05776t}} = \ln{0.25}$

$-0.05776t = \ln{0.25}$

$0.05776t = -\ln{0.25}$

$t = -\frac{\ln{0.25}}{0.05776}$

$t = 24$

It would take 24 minutes for the element to decay to 50 grams

6 0

3 years ago

The sum of three consecutive odd integers is 165. what are they

Sveta_85 [38]

N+(n+2)+(n+4)=165
add everything together to get
3n+6=165
Subtract 6 from each side
3n=159
divide by 3
n=53
the numbers are 53,55,57

7 0

2 years ago

(05.03 MC)

Jlenok [28]

Look it up on khan academy

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2 years ago