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Ilia_Sergeevich [38]
4 years ago
12

I need help on this please

Mathematics
1 answer:
yulyashka [42]4 years ago
3 0

Answer:

C

Step-by-step explanation:

The equation of C is 4th-degree, so is definitely non-linear.

___

The equation of E can be multiplied by y to get x +y = 2y, which is a linear equation. It graphs as a straight line, so can be called linear on that basis. However, it has a "hole" at y=0, so could arguably be called non-linear.

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If you where to go to a party would you pee or poop?
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pee

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If 5/8 of the people in a water aerobics class are over age 65 and 1/4 of the people in the class are under age 40, what fractio
agasfer [191]

Answer:

7/8

Step-by-step explanation:

You just need to add the two fractions together. Since no one can be both, no  other revision is needed.

5/8 + 1/4 = 5/8 + 2/8 = 7/8

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A rectangular prism has a volume of 600 cubic inches lf the height of the prism is 5 inches and the width is 10 inches what is t
goldfiish [28.3K]

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Step-by-step explanation:

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7 0
3 years ago
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
I really need help...
ira [324]
The 1st is 3 2/16

Good luck with the others.
3 0
3 years ago
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