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jok3333 [9.3K]
3 years ago
8

Consider the equation:

Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0

Answer:

x² + 2x - 15 = 0

x² + 2x + 1 = 16

(x + 1)² = 16

You can then go forward with that to solve it:

x + 1 = √16

x = -1 ± √16

x = -1 ± 4

x = 3, -5

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Value of x in log5x = 4logx5 is
olchik [2.2K]
Log5 x=4 logx 5
Ln x/ln5=4(ln5 / ln x)                                 logx z=ln x / ln z
least common multiple=ln5 * ln x

ln²x=4ln²5
√(ln² x)=√(4 ln²5)
ln x=2ln 5
x=e^2ln5=25

Answer: x=25.

4 0
3 years ago
Mias dog weighs 32.6 pounds. Letties dog weighs 3.8 times as much as Mias you. What does Letties dog weigh in pounds?
Whitepunk [10]
Hello!

We are given the weight of Mia's dog and told to find the weight of Lettie's dog based on the known relationship. Using these given values, we can create the following equation (let "w" represent the total weight of Lettie's dog):

w = 32.6(3.8)

Simplify the right side of the equation:

w = 123.88

We have now proven that Lettie's dog weighs 123.88 lbs.

I hope this helps!
6 0
3 years ago
Read 2 more answers
What property is (3x10)x8=3x(10x8)
mylen [45]
(3 x 10) x 8 = 3 x (10 x 8)
this is called the associative property of multiplication.
it states : (a * b) * c = a * (b * c)
7 0
3 years ago
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We have seen that isosceles triangles have two sides of equal length. The angles opposite these sides have the same measure. Use
Naddik [55]

Question has missing figure, the figure is in the attachment.

Answer:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

Step-by-step explanation:

Given,

We have an isosceles triangle which we can named it as ΔABC.

In which Length of AB is equal to length of BC.

And also m∠B is equal to m∠C.

ext.m∠C= 115°(Here ext. stands for exterior)

We have to find the measure of angles angles 1 through 5.

Solution,

For ∠1.

∠1 and ext.∠C makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle1+ext.\angle C=180\°

On putting the values, we get;

\angle 1+115\°=180\°\\\\\angle1=180\[tex]\therefore m\angle2=65\°-115\°=65\°[/tex]

Thus the measure of ∠1 is 65°.

For ∠2.

Since the given triangle is an isosceles triangle.

So, m\angle1=m\angle2

Thus the measure of ∠2 is 65°.

For ∠3.

Here ∠1, ∠2 and ∠3 are the three angles of the triangle.

So we use the angle sum property of triangle, which states that;

"The sum of all the angles of a triangle is equal to 180°".

\therefore \angle1+\angle2+\angle3=180\°

Now we put the values and get;

65\°+65\°+\angle3=180\°\\\\130\°+\angle3=180\°\\\\\angle3=180\°-130\°=50\°

Thus the measure of ∠3 is 50°.

For ∠4.

∠4 and ∠2 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle2 +\angle 4 =180\°

Substituting the values of of angle 2 to find angle 4 we get;

65\°+ \angle 4 = 180\°\\\\ \angle 4 = 180\°-65\°\\\\\angle 4= 115\°

Thus the measure of ∠4 is 115°.

For ∠5.

∠4 and ∠5 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle4 +\angle 5 =180\°

Substituting the values of of angle 4 to find angle 5 we get;

115\°+ \angle 5 = 180\°\\\\ \angle 5 = 180\°-115\°\\\\\angle 5= 65\°

Thus the measure of ∠5 is 65°.

Hence:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

6 0
3 years ago
Solve 58÷4(6×9)+7(7×3)<br><br>​
alina1380 [7]
Step:

58/4x54+7x21 =
783+7x21 =
783+147 =
930
8 0
3 years ago
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