=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
9514 1404 393
Answer:
(x, y) = (2/5, 1)
Step-by-step explanation:
Substitute for y and solve for x.
1 = -5x +3
-2 = -5x . . . . . . subtract 3
2/5 = x . . . . . . divide by -5
The solution is (x, y) = (2/5, 1).
Quarters equal 25 cents so multiply 25 x32
Answer:
40001/20
Step-by-step explanation:
might want to fact check it just in case.
Answer:
The answer is option C
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the equation of the line first find the slope
The line has a y intercept of 2 which is
(0 , 2)
Slope of the line using points
( 1 ,1) and (0,2) is
So the equation of the line using point (1,1) is
y - 1 = - 1(x - 1)
y - 1 = - x + 1
x + y - 1 - 1 = 0
We have the final answer as
<h3>x + y - 2 = 0</h3>
Hope this helps you
