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White raven [17]
3 years ago
15

There are 4 new seats in each row in a school auditorium. There are 15 rows in the auditorium. Each new seat costs $74.

Mathematics
1 answer:
svlad2 [7]3 years ago
7 0

$4,440

Multiplied

4

60

$74

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Which of the following sets of number does square of 121 NOT belong
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D

Step-by-step explanation:

Squaring 121 will still be a real number, a rational number, and an integer. Therefore, it is not an irrational number.

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The Global Footprint Network is an organization dedicated to the advancement of environmental sustainability around the world. T
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49 7th graders and 35 8th graders show up at football tryouts choose a ratio that represents 7th to 8th graders at tryouts?
Alja [10]

Answer:

7:5

Step-by-step explanation:

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Simply find the total medium cofees sold
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67\%
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3 years ago
Read 2 more answers
The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 . a.
Anastasy [175]

Answer:

a) 0.073044

b) 0.75033

c) The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

Step-by-step explanation:

The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 .

a. Find the probability that an individual distance is greater than 218.00 cm.

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 218

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

For x > 218

z = 218 - 205.5/8.6

z = 1.45349

Probability value from Z-Table:

P(x<218) = 0.92696

P(x>218) = 1 - P(x<218) = 0.073044

b. Find the probability that the mean for 15 randomly selected distances is greater than 204.00

When = random number of samples is given, we solve using this z score formula

z = (x-μ)/σ/√n

where

x is the raw score = 204

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

n = 15

For x > 204

Hence

z = 204 - 205.5/8.6/√15

z = -0.67552

Probability value from Z-Table:

P(x<204) = 0.24967

P(x>204) = 1 - P(x<204) = 0.75033

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

3 0
3 years ago
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