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hoa [83]
3 years ago
5

Evaluate 3+jk+k^3 when j=2 and k=6

Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

3 + 2(6) + 6^3 = 231

Step-by-step explanation:

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The area of a trapezium is 34 cm and the length one of its parallel side is
Natasha_Volkova [10]

Answer:

6.6 cm.

Step-by-step explanation:

The area of a trapezium A = (h/2)(a + b)    where h = the height, a and b are the length of the parallel sides.

So substituting the given values in this formula:

34 = (4/2)(10.4 + b)

34 =  2(10.4 + b

34 = 20.8 + 2b

2b = 34 - 20.8 = 13.2

b = 6.6 cm.

3 0
3 years ago
The weight of 3 eggs is shown. Identify the constant of proportionally of total weight to number of eggs. The weight of the eggs
HACTEHA [7]
It would be 48g per egg
8 0
3 years ago
Can someone help me plz am stuck on this.
chubhunter [2.5K]
First Question

circumference = pi * diameter

diameter = circumference/pi = 94.2 in./3.14 = 30 in.

The wheels have a 30-inch diameter.
-----------------------------------------------------------------------
Second question

The area of a circle: area = pi * r^2

radius = diameter/2 = 94.2 in./2 = 47.1 in.

area = pi * r^2 = 3.14 * 47.1 in. * 47.1 in. = 6966 in.^2

Answer: 6966 in.^2
-----------------------------------------------------------------------
Third question

The piece of felt has a width equal to the diameter of the wheel. The length has to be the same as 4 diameters.

4 * 94.2 in. = 376.8 in.

Answer: 376.8 in.
6 0
4 years ago
Which is the area of a circle with circumference of 15.7 units?( Use 3.14 for )
damaskus [11]
A = π(r²) --- r is radius

C = πd --- d is diameter

First, the circumference must be found. If the circumference is 15.7, plug it in.

15.7 = πd

We know what pi is.

15.7 = 3.14 (d)

Now, simply divide 3.14 by 15.7 to find the diameter (d). You get 5. Since the radius is half of the diameter, the radius is 2.5. Plug this into the area formula, and plug pi in, too.

A = 3.14(2.5²) 

2.5 to the second power is 6.25.

A = 3.14(6.25)

Tada! Multiply, and you're left with 19.625!
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4 0
3 years ago
Read 2 more answers
I need help on #15<br> I do not know how to begin this problem.
Umnica [9.8K]
The first limit is known as a left-hand limit. We're approaching x = 3 from the left. This means we start with values smaller than x = 3, say x = 2.5 and move closer to x = 3.

Because x is starting off smaller than 3, we use the first piece of the piecewise function. This is the piece that corresponds to x < 3. So we plug x = 3 into that piece to get

2x^2 - x = 2(3)^2 - 3 = 2(9) - 3 = 18 - 3 = 15

So the result for the left-hand limit is 15.

----------------------------------------------------------

The right hand limit will have us start on the other side of x = 3. We start at x = 3.5 and move closer to x = 3. So we'll use the x \ge 3 portion.

Plug x = 3 into the second piece to get
3 - x = 3 - 3 = 0

--------------------------------------------------------------------------

The result of the left-hand limit was 15
The result of the right-hand limit was 0

The fact that the results do not match up means that the overall limit at x = 3 does NOT exist. 
5 0
3 years ago
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