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kari74 [83]
3 years ago
15

The data represents the body mass index​ (BMI) values for 20 females. Construct a frequency distribution beginning with a lower

class limit of 15.0 and use a class width of 6.0. 17.7. 33.5. 26.6 24.7
28.8. 23.8. 18.3. 22.1
19.2. 22.6. 22.7. 38.9
27.3. 44.9. 32.2. 23.9
Mathematics
1 answer:
Wittaler [7]3 years ago
4 0

Kindly note that the data supplied is not up to 20. Hence, the answer will be based on the number of data given.

Answer:

Step-by-step explanation:

Given the following data:

BMI of 20 females :

17.7. 33.5. 26.6 24.7

28.8. 23.8. 18.3. 22.1

19.2. 22.6. 22.7. 38.9

27.3. 44.9. 32.2. 23.9

Lower class limit (LCL) = 15.0

Class width = 6.0

Class_interval_____frequency

15.0 - 20.9 _________3

21.0 - 26.9 _________7

27.0 - 32.9 _________3

33.0 - 38.9 _________2

39.0 - 44.9 _________1

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Find the value<br> 25 points for you, a thanks, 5 star rating and brainliest to the right answer
tigry1 [53]

Answer:

4/5

Step-by-step explanation:

Sin is opposite / hypotenuse

Sin x= 16/20

16/20= 4/5

4 0
2 years ago
Carlotta collects stamps. She owns f stamps from France and 15 more than twice this amount of American stamps. Which expression
Digiron [165]

Answer:

D: 2f+15

Step-by-step explanation:

f is the number of stamps from France that Carlotta owns.

Twice this amount is 2f

Then, 15 more than twice this amount is 2f + 15, and this is the expression that represents the number of American stamps that Carlotta owns

7 0
3 years ago
Find the equation of the line with slope = 6 and passing through (6,43). Write your equation in the form y = m x + b .
gayaneshka [121]

Answer:

y = 6x + 7.

Step-by-step explanation:

Using the point-slope form of a line

y - y1 = m(x - x1)

m = 6, x1 = 6 and y1 = 43:

y - 43 = 6(x - 6)

y - 43 = 6x - 36

y = 6x - 36 + 43

y = 6x + 7.

5 0
3 years ago
Please someone help me with this word problem for my math class T.T
olga55 [171]

Answer:

<u>Perimeter</u>:

= 58 m (approximate)

= 58.2066 or 58.21 m (exact)

<u>Area:</u>

= 208 m² (approximate)

= 210.0006 or 210 m² (exact)

Step-by-step explanation:

Given the following dimensions of a rectangle:

length (L) = \sqrt{252} meters

width (W) = \sqrt{175} meters

The formula for solving the perimeter of a rectangle is:

P  = 2(L + W) or 2L + 2W

The formula for solving the area of a rectangle is:

A = L × W

<h2>Approximate Forms:</h2>

In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.  

13² = 169

14² = 196

15² = 225

16² = 256

Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width).  We can use these values to approximate the perimeter and the area of the rectangle.

P  = 2(L + W)

P = 2(13 + 16)

P = 58 m (approximate)

A = L × W

A = 13 × 16

A = 208 m² (approximate)

<h2>Exact Forms:</h2>

L = \sqrt{252} meters = 15.8745 meters

W = \sqrt{175} meters = 13.2288 meters

P  = 2(L + W)

P = 2(15.8745 + 13.2288)

P = 2(29.1033)

P = 58.2066 or 58.21 m

A = L × W

A = 15.8745 × 13.2288

A = 210.0006 or 210 m²

8 0
2 years ago
Consider the following equation. y = 1/3x + 10. Which of the following lines is perpendicular to the one a above ?
seraphim [82]

Answer:

D. Y=3x+10

Step-by-step explanation:

5 0
3 years ago
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