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Kisachek [45]
3 years ago
14

If f(x) = 4x + 12 is graphed on a coordinate plane, what is the y-intercept of the graph?

Mathematics
1 answer:
Ierofanga [76]3 years ago
6 0

Answer:

it's -4 I just took the test and you will get it write

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3 years ago
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I need help fast I appreciate the help
Neko [114]

Answer:

3/5

Step-by-step explanation:

Sin is opp/hyp so it would be 30/50 in lowest form it would become 3/5

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2 years ago
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Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

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4:40 more ml

Step-by-step explanation:

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How many different passwords are possible if each password consists of six characters where each character is either an uppercas
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<span><span>1,867,866,560</span><span>1,867,866,560</span></span><span>.</span>
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3 years ago
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