Answer:
y=12x-16
Step-by-step explanation:
You want to find the equation for a line that passes through the point (3,20) and has a slope of 12.
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was 12. So you can right away fill in the equation for a line somewhat to read:
y=12x+b.
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(3,20). When x of the line is 3, y of the line must be 20.
Because you said the line passes through this point, right?
Now, look at our line's equation so far: . b is what we want, the 12 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (3,20).
So, why not plug in for x the number 3 and for y the number 20? This will allow us to solve for b for the particular line that passes through the point you gave!.
(3,20). y=mx+b or 20=12 × 3+b, or solving for b: b=20-(12)(3). b=-16.
The equation of the line that passes through the point (3,20) with a slope of 12
is
y=12x-16
