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7nadin3 [17]
3 years ago
9

Three fifths of the members of a hiking club went on the last hiking trip. If 39 people went on the trip , how many are in the c

lub?
Mathematics
1 answer:
finlep [7]3 years ago
4 0

Step-by-step explanation:

1. Since 39 is 3/5 of the club, divide by 3 to get 1/5 of the club

2. 1/5 of the club is 13 people

3. Multiply 13 by 5 to get 5/5 of the club (which is the whole club)

4. The whole club is 65 people

5. You can check it because 65×3/5=39

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13. Write an equation for the given function given the amplitude, period, phase shift, and vertical shift.
Paul [167]

Answer:

y=4sin(\frac{2\pi(t+\frac{4}{3}\pi ) }{4\pi } )-2

Step-by-step explanation:

Let's start with the original function.

y=a sin\frac{2\pi t}{T}

We can immediately fill in the amplitude 'a' and period 'T' , as the question defines these for us, and provides values for 'a' and 'T', 4 and 4\pi respectively.

y=4sin(\frac{2\pi t}{4\pi } )

Now we only have phase shift and vertical shift to do. Vertical shift is very easy, you can just add it to the end of the right side of the expression. A positive value will shift the graph up, while a negative value will move shift the graph down. We have '-2' as our value for vertical shift, so we can add that on as so:

y=4sin(\frac{2\pit }{4\pi } )-2

Now phase shift the most complicated of the transformations. Basically, it is just movement left or right. A negative phase shift moves the graph right, a positive phase shift moves the graph left (I know, confusing!). Phase shift applies directly to the x variable, or in this case the t variable. To achieve a -4/3 pi phase shift, we need to input +4/3 pi into the function, because of the aforementioned negative positive rule. Here is what the function looks like with the correct phase shift:

y=4sin(\frac{2\pi(t+\frac{4}{3}\pi ) }{4\pi } )-2

This function has vertical shift -2, phase shift -4/3 \pi, amplitude 4, and period 4\pi.

Desmos.com/calculator is a great tool for learning about how various parts of an equation affect the graph of the function, If you want you can input each step of this problem into desmos and watch the graph change to match the criteria.

8 0
3 years ago
John wants to find the center of a wall so he can hang a picture. He measures the wall and determines it is 65.25" wide. 65.25"
antiseptic1488 [7]

Option B is correct.

John wants to find the center of a wall so he can hang a picture. He measures the wall and determines it is 65.25" wide.

Here, 65.25" is Quantitative, continuous

There are two types of quantitative data or numeric data: continuous and discrete.

As a general rule, counts are discrete and measurements are continuous. A continuous data can be recorded at many different points (length, size, width, time, temperature, etc.)

So, option B is the answer.


3 0
3 years ago
Please help me<br>simplify<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B32%20-%20%20%5Csqrt%7B50%7D%20%7D%20" id="TexFormul
Mnenie [13.5K]

Answer:

\sqrt{32-5\sqrt{2} }

Step-by-step explanation: I hope it helps :)

\sqrt{32-\sqrt{50} } \\\\simplify \: \sqrt{50} \:to \:5\sqrt{2}  \\\\= \sqrt{32-5\sqrt{2} } \\\\Decimal Form: 4.992888

5 0
3 years ago
Please need help on this thank you
Katen [24]

multiply width times the height to get the rectangle area

5 x 7 = 35 units squared

I may be wrong but I think you may be over complicating it its okay I do that a lot too


8 0
3 years ago
Read 2 more answers
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2 years ago
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