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RUDIKE [14]
3 years ago
14

Y=2x-1 2x+y=3 how do i solve this substitution problem

Mathematics
1 answer:
nika2105 [10]3 years ago
8 0

Step-by-step explanation:

y=2x-1 \:  \:  \:  \:  \:  \:  \: ..(1) \\ 2x+y=3 \:  \:  \:  \:  \:  \:  \:...(2) \:  \:  \:  \:  \:  \: (given)

put equation 1 in equation 2

2x+2x - 1=3 \\ 4x = 4 \\ x =   \frac{4}{4}  = 1 \\  \\ x = 1 \\  \\

2(1)+y=3 \\ 2 + y = 3 \\ y = 3 - 2 \\ y = 1

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I watched a video and didn't get my free answer, can I have some help,
vazorg [7]

Answer:

y + 13 = 5(x + 2)

Step-by-step explanation:

The slope-intercept form of the equation of a line is

y = mx + b,

where m = slope, and b = y-intercept.

From the slope-intercept equation y = 5x - 3, we see that the slope of the line is 3.

The point-slope form of the equation of a line is:

y - y1 = m(x - x1)

where m = slope, and (x1, y1) is a point on the line.

We have point (-2, -13), so x1 = -2, and y1 = -13.

We also have slope 5, so m = 5.

Now we use the coordinates of the given point and the slope in the point-slope equation.

y - (-13) = 5(x - (-2))

We simplify to get

y + 13 = 5(x + 2)

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3 years ago
A wall in Marcus's bedroom is 8 2/5 feet high and 16 2/3 feet long If he paints 1/2 of the wall blue, how many square feet will
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4 years ago
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What number should be added to both sides of the equation to complete the square x^2+3x=6
Allisa [31]
Take half of the coefficient of x:  It is 3, and half that is 3/2.


Then   <span>x^2+3x=6  becomes:

</span><span>           x^2+3x + (3/2)^2 =6 + (3/2)^2, and

             (x+3/2)^2 = 6 + 9/4

You were not asked to solve the equation, but why not do it for the practice?

</span>Solve (x+3/2)^2 = 6 + 9/4 for x.  There will be 2 values.
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4 years ago
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Answer:

hope this help you

of my handwriting is bad then sorry.

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3 years ago
10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.
erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

p = \frac{4}{6} = 0.6667

10 normal six sided dice are thrown.

This means that n = 10

Find the probability of obtaining at least 8 failures.

This is:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951

P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867

P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174

Then

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992

0.2992 = 29.92% probability of obtaining at least 8 failures.

8 0
3 years ago
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