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weqwewe [10]
2 years ago
10

How many inches are in 10 feet

Mathematics
1 answer:
Rufina [12.5K]2 years ago
6 0

Answer:

120 <em>inches</em>

Step-by-step explanation:

Since we know 1 foot is 12 inches, we can multiply the amount of inches in 1 foot by 10 feet to get 120 inches.

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Can you guys help me please<br><br> simplify:<br> (4a^2b^3c^5)^3
KatRina [158]

Answer:

64a^6b^9c^15

hope that helps

3 0
2 years ago
Identify the quotient in the form a + bi. HELP ASAP PLEASE!!
Step2247 [10]

Solving the expression \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

So, Option A is correct.

Step-by-step explanation:

We need to solve the expression: \frac{4-5i}{2+3i}

Multiplying and dividing by 2-3i

=\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}\\=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,know\,\, i^2=-1\\=\frac{8-12i-10i+15(-1)}{4-9(-1)}\\=\frac{8-15-12i-10i}{4+9}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}

So, solving the expression \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

So, Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

  • brainly.com/question/10736268
  • brainly.com/question/4678474

#learnwithBrainly

8 0
3 years ago
FaSSSSSSTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT and thanks yall are fast
Mama L [17]

Answer:

120 degrees

Step-by-step explanation:

It's a vertical angle, meaning that it is congruent to the one on the opposite side of it.

5 0
2 years ago
A regular fish tank is 18 in wide 12 in deep and 24 in tall what is the volume of that fish tank​
Lady bird [3.3K]

Answer:

(4,5 feet)³=4,5³ cubic feet

Step-by-step explanation:

6 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
3 years ago
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