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3 years ago

A 4.5 pound bag of apples cost $22.50. What is the unit price?

Mathematics

2 answers:

Reptile [31]3 years ago

6 0

Answer:

The unit price is $5.

irakobra [83]3 years ago

4 0

Answer:

$5.00.

Step-by-step explanation:

This is 22.5 / 4.5

= $5.00

You might be interested in

If g (x) = 3x²-4, then find g (-3)

Semenov [28]

Answer:

g(-3) = 23

Step-by-step explanation:

This question is telling us that x = -3. Knowing this, we can plug x into the equation and solve to find g(-3).

$g(-3) = 3(-3)^{2} -4$

$g(-3) =3(9)-4$ Square -3 to get 9

$g(-3) = 27-4$ Multiply 9 by 3 to get 27

$g(-3) = 23$ Subtract 4 from 27 to get 23

Thus, g(-3) is equal to 23.

I hope this helps! Good luck!

6 0

2 years ago

What strategie do u use to divide 98 divided by 7

sineoko [7]

You can break 98 into 2 49's. Hopefully, we know that 49 is 7 * 7, so 98 is 7 * 14. The correct answer is 14. :)

7 0

3 years ago

A tax assessor wants to assess the mean property tax bill for all homeowners in a certain state. From a survey ten years ago, a

Jet001 [13]

Answer:

The answer is below

Step-by-step explanation:

From the table, the mean (μ) = 1390.75 and the standard deviation (σ) = 518.75

The confidence level (C) = 90% = 0.9

α = 1 - C = 1 - 0.9 = 0.1

α/2 = 0.1 / 2 = 0.05

The z score of α/2 (0.05) is the same as the z score of 0.45 (0.5 - 0.05) which is equal to 1.645.

The margin of error (E) is given as:

$E=Z_\frac{\alpha}{2}*\frac{\sigma}{\sqrt{n} } \\\\E=1.645*\frac{518.75}{\sqrt{14} } =228.07$

The confidence interval = μ ± E = 1390.75 ± 228.07 = (1162.68, 1618.82)

The confidence interval is between 1162.68 and 1618.82.

7 0

3 years ago

A sum of money is divided into the ratio 3:4. The larger portion is then divided into 3 parts in

vivado [14]

Step-by-step explanation:

this is your answer.........

5 0

2 years ago

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

6 0

2 years ago