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Natali [406]
2 years ago
6

Which is a factor of 15xy − 45x − 6y + 18?

Mathematics
2 answers:
Nadya [2.5K]2 years ago
8 0
The factor of <span>15xy − 45x − 6y + 18 is 3(y-3)(5x-2).</span>
AleksandrR [38]2 years ago
6 0

15xy−45x−6y+18


3(y−3)(5x−2)

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Bag contains 4 red marbles, 2 blue marbles, 1 purple
GaryK [48]

Answer:

432

Step-by-step explanation:

6 0
2 years ago
Contains the x intercept of 4x-y=8 and the point (-4,3)
nydimaria [60]
<span>1.       </span><span>4x –y = 8, the point (-4, 3)
Let’s say y = 0
=> 4x – 8
=> 4x / 4 = 8 /4
=> x = 2
So the point is (2 , 0).
Now, we have 2 forms, the (2,0) and the (-4, 3)
=> (y2 – y1)(x2 – x1) = m
=> m = (0 - 3)(2-(-4))
=> m = (0 - 3)(2+4)
=>  m = (-3)(6)
=> m = -1/2
Thus,
y = -1/2x + a
=> 0 = -1 + a so a = 1
y = -x/2 + 1</span>



7 0
3 years ago
Read 2 more answers
How to state gradient and y-intercept
n200080 [17]

In summary. The graph of each equation is a straight line, m is the gradient of the line and c is the y-intercept. Conversely, if a straight line has gradient m and y-intercept c it has equation y = mx + c.

7 0
2 years ago
for the opening day of a carnival, 800 admission tickets were sold. The receipts totaled $3775. Tickets for children cost $3 eac
zloy xaker [14]
Total tickets sold  = 800
Total revenue = $3775

Ticket costs:
$3  per child,
$8  per adult,
$5 per senior citizen.

Of those who bought tickets, let
x =  number of children 
y = number of adults
z = senior citizens

Therefore
x + y + z = 800                   (1)
3x + 8y + 5z = 3775           (2)

Twice as many children's tickets were sold as adults. Therefore
x = 2y                                (3)

Substitute (3) into (1) and (2).
2y + y + z = 800, or
3y + z = 800, or
z = 800 - 3y                        (4)
3(2y) + 8y + 5z = 3775, or
14y + 5z = 3775                 (5)

Substtute (4) nto (5).
14y + 5(800 - 3y) = 3775
-y = -225
y = 225
From (4), obtain
z = 800 - 3y = 125
From (3), obtain
x = 2y = 450

Answer:
The number of tickets sold was:
450 children,
225  adults,
125 senior citizens.
6 0
3 years ago
Paul paid $ 25.50 for 3 cups of hot chocolate and cups of tea. The cost of each cup of tea was 2/3 the cost of each cup of hoy c
Allushta [10]

Let the cost of one cup of hot chocolate  be = x

Let the cost of one cup of hot tea be = y

Paul paid $ 25.50 for 3 cups of hot chocolate and 4 cups of tea.

Equation becomes = 3x+4y=25.50   ...(1)

As given, the cost of each cup of tea was 2/3 the cost of each cup of hot chocolate.

y=\frac{2x}{3}   .... (2)

Putting the value of y from (2) in (1)

3x+4(\frac{2x}{3})=25.50

=3x+\frac{8x}{3}=25.50

=\frac{9x+8x}{3}=25.50

=17x=76.5

x=4.5

y=\frac{2x}{3}

=\frac{2*4.5}{3}

y =3

Hence each cup of hot chocolate is $4.50

Each cup of tea is $3.

7 0
2 years ago
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