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Natali [406]
2 years ago
6

Which is a factor of 15xy − 45x − 6y + 18?

Mathematics
2 answers:
Nadya [2.5K]2 years ago
8 0
The factor of <span>15xy − 45x − 6y + 18 is 3(y-3)(5x-2).</span>
AleksandrR [38]2 years ago
6 0

15xy−45x−6y+18


3(y−3)(5x−2)

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Fine the value of 5.8÷12
Paha777 [63]
<span>0.48333333333 or if u round it off it would be 0.48</span>
4 0
2 years ago
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Which ordered pair is the solution to the system of equations? {x+3y=-12, y= 1/3x-6?
Julli [10]

For this, I'll be using the substitution method. Since y = 1/3x - 6, replace the y variable in the first equation with 1/3x - 6 and solve for x:

x+3(\frac{1}{3}x-6)=-12\\ x+x-18=-12\\ 2x-18=-12\\ 2x=6\\ x=3

Now that we have the value of x, plug it into either equation to solve for y:

3+3y=-12\\ 3y=-15\\ y=-5\\ \\ y=\frac{1}{3}*3-6\\ y=1-6\\ y=-5

<h3><u>In short, the solution to this equation is (3,-5).</u></h3>
5 0
2 years ago
Please help <br><br><br> will mark brainlist
stira [4]

ANSWER:

J:

(5,-10)

K:

(15,-6)

L:

(15,-15)

4 0
3 years ago
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A teacher always arranged the content0 of each lessons to Year 10 as teaching and practising learnt skills in the ratio 2:3. α I
Paraphin [41]
I'd say (a) = 52.5 minutes or 52 minutes and 30 second

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3 0
3 years ago
Solve for x and y.<br><br> 4x-3y=16<br> -2x+4y=-2<br><br> DUE 2/7/17!
Trava [24]
\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.

<span>Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
</span>\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.
\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.
--------------------
5y = 12
\boxed{\boxed{y =  \frac{12}{5}}}\end{array}}\qquad\quad\checkmark

Let's replace the value found in the first equation:
4x-3y=16\:(I)
4x-3*( \frac{12}{5}) =16
4x -  \frac{36}{5} = 16
least common multiple (5)
\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}
20x - 36 = 80
20x = 80 + 36
20x = 116
x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark



4 0
3 years ago
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